在整个月中循环每月的日子答案

【问题标题】：Loop the days of the month throughout the whole month在整个月中循环每月的日子
【发布时间】：2015-10-15 10:12:15
【问题描述】：

我正在构建多日历，我有一个横向的界面：

我正在尝试运行一周中的几天S,M,T,W,T,F,S 整个月，而不是图片中的前 7 个。

绘制日历的函数：

//our case "SUN" 
if(AC_START_DAY=="sun"){
    for($k=0; $k<7; $k++){
        $weekday = mb_substr($lang["day_".$k.""],0,1,'UTF-8');
        $list_day_titles.='<li class="cal_weekday"> '.$weekday.'</li>';
    }
}
//If we chose Monday as start week.
else{
    if ($first_week_day == 0)   $first_week_day =7;
    for($k=1; $k<=7; $k++){
        if($k==7)   $weekday = mb_substr($lang["day_0"][0],0,1,'UTF-8');
        else        $weekday = mb_substr($lang["day_".$k.""],0,1,'UTF-8');
        $list_day_titles.='<li title="'.$lang["day_".$k.""].'"> '.$weekday.'</li>';
    }
}

语言文件：

$lang["day_0"]      =   "Sunday";
$lang["day_1"]      =   "Monday";
$lang["day_2"]      =   "Tuesday";
$lang["day_3"]      =   "Wednesday";
$lang["day_4"]      =   "Thursday";
$lang["day_5"]      =   "Friday";
$lang["day_6"]      =   "Saturday";

已经定义

$month=sprintf("%02s",$month);
//  define vars
$today_timestamp    =   mktime(0,0,0,date('m'),date('d'),date('Y'));    #   current timestamp - used to check if date is in past
$this_month         =   getDate(mktime(0, 0, 0, $month, 1, $year));     #   convert month to timestamp
$first_week_day     = $this_month["wday"];                              #   define first weekday (0-6)
$days_in_this_month = cal_days_in_month(CAL_GREGORIAN,$month,$year);    #   define number of days in week
$day_counter_tot    =   0; #    count total number of days showin INCLUDING previous and next months - use to get 6th row of dates

看起来$lang["day_".$k.""] 只是在计算从 0 到 6 的天数。我怎样才能循环到月底？

注意：我尝试增加 $k<7 只是出现更多的空蓝框。

【问题讨论】：

从这些函数开始，需要知道它们处理的月份，以便计算该月有多少天，因此您可以将循环限制更改为正确的数字输出天数

标签： php loops for-loop

【解决方案1】：

使用循环到 30/31 天。

然后改变这一行

$weekday = mb_substr($lang["day_".$k.""],0,1,'UTF-8');

到

$weekday = mb_substr($lang["day_".$k%7.""],0,1,'UTF-8');

这应该给你每个星期天的第 0 天。

0 % 7 = 0 (sunday)
1 % 7 = 1 (monday)
...
7 % 7 = 0 (sunday again)
8 % 7 = 1 (monday again)

【讨论】：

【解决方案2】：

您可以使用此代码生成当月的所有日期。

for ($date = strtotime(date('Y-m-01')); $date < strtotime(date('Y-m-t')); $date = strtotime("+1 day", $date)) {
        echo date("l-d", $date)."<br>";
    }

将打印当月的所有天数，如下所示。

Thursday-01
Friday-02
Saturday-03
Sunday-04
Monday-05
Tuesday-06
Wednesday-07
Thursday-08
Friday-09
Saturday-10
Sunday-11
Monday-12
Tuesday-13
Wednesday-14
Thursday-15
Friday-16
Saturday-17
Sunday-18
Monday-19
Tuesday-20
Wednesday-21
Thursday-22
Friday-23
Saturday-24
Sunday-25
Monday-26
Tuesday-27
Wednesday-28
Thursday-29
Friday-30

【讨论】：

【解决方案3】：

看起来你几乎做对了。您只需稍微修改您的代码，使其按您希望的方式工作。您只需将代码更改为：

$number_of_days_in_the_future = 42; // Here you can put in the number of days for which you want to display the corresponding letter, and based on your screenshot that is 42
//our case "SUN" 
if(AC_START_DAY=="sun"){
    for($i=0; $i<$number_of_days_in_the_future; $i++){
        $k = $i % 7;
        $weekday = mb_substr($lang["day_".$k.""],0,1,'UTF-8');
        $list_day_titles.='<li class="cal_weekday"> '.$weekday.'</li>';
    }
}
//If we chose Monday as start week.
else{
    if ($first_week_day == 0)   $first_week_day =7;
    for($i=1; $i<=$number_of_days_in_the_future; $i++){
        $k = $i % 7;
        if($k==7)   $weekday = mb_substr($lang["day_0"][0],0,1,'UTF-8');
        else        $weekday = mb_substr($lang["day_".$k.""],0,1,'UTF-8');
        $list_day_titles.='<li title="'.$lang["day_".$k.""].'"> '.$weekday.'</li>';
    }
}

请注意，我只是尝试修复您的代码，使其按您的预期工作。可能有一个更优雅的解决方案，但我真的不知道你的完整代码，所以我只是猜测我是否试图为你提供另一种方法。

希望对你有所帮助。

干杯

【讨论】：