杰克逊反序列化为 POJO 没有注释答案

【问题标题】：Jackson deserialize to POJO without annotations杰克逊反序列化为 POJO 没有注释
【发布时间】：2015-10-27 11:42:39
【问题描述】：

我生成了这个 json，我想反序列化为 POJO 列表

{
"members":
    [
      {"id":"947","route":"123","milkNo":"Z5623","nationalId":"65326812","firstName":"Server","otherName":"Farmer","country":"Kenya","county":"Nyandarua","address":"South Kinangop","phone1":"0752365258","phone2":"0712456321","email":"yunus.awse@gmail.com","sent":"0","remoteServer":1,"createdAt":"2015-10-21 11:17:31","updatedAt":"0000-00-00 00:00:00"}],

 "milkPayment":
     [
        {"id":"3","memberNo":"1","quantity":"40","price":"36","amount":"1437.5","deductions":"16390","payable":"-14952.5","date":"2015-10-16","remoteServer":1,"createdAt":"2015-10-16 10:26:10"}
     ],
 "advancePayment":[]
}

如何仅提取 members 数组部分，以便我可以在以下代码中提供它以获取成员列表

ObjectMapper objectMapper = new ObjectMapper();

List<Member> newMemberDeductions = objectMapper.readValue(a, objectMapper.getTypeFactory().constructCollectionType(List.class, Member.class));

【问题讨论】：

标签： java json jackson

【解决方案1】：

一种方法是使用JsonNode（从 json 遍历所需的键）。试试这个：

ObjectMapper objectMapper = new ObjectMapper();
JsonNode node = objectMapper.readTree(new File("D:/Tests/sample.txt"));
node = node.findValue("members");
List<Member> newMemberDeductions = objectMapper.readValue(node.toString(), objectMapper.getTypeFactory().constructCollectionType(List.class, Member.class));

这里我把你的 json 作为文件放在D:/Tests/sample.txt

【讨论】：