查找将来某个时间具有相应记录的记录[关闭]

Question

我有具有以下布局的记录表（目前是列存储）：

id  | person_id | practice_key | order_date
-------------------------------------------
1   | 001       | prac-A       | 1501098844
2   | 001       | prac-A       | 1516996444
...

id，person_id 是 UUID（存储为 CHAR），practice_key 是 VARCHAR，order_date 是存储为 NUMERIC 的纪元秒数，

我只想选择至少六个月后拥有order_date 的person_id。

我尝试了以下方法：

SELECT MIN(DATE(FROM_UNIXTIME(order_date))) min_order_date, person_id 
FROM the_table WHERE 
DATE(FROM_UNIXTIME(order_date)) >= 
DATE_ADD(MIN(DATE(FROM_UNIXTIME(order_date))), INTERVAL 6 MONTH);

和

SELECT MIN(DATE(FROM_UNIXTIME(order_date))) min_order_date, person_id 
FROM the_table WHERE 
DATE(FROM_UNIXTIME(order_date)) >= 
DATE_ADD(MIN(DATE(FROM_UNIXTIME(order_date))), INTERVAL 6 MONTH)
GROUP BY person_id;

但我收到以下错误：[HY000][1111] Invalid use of group function

我正在使用 MemSQL v6.0

Answer 1

在澄清他的立场后，我会尝试以下。它只是简单地加入桌子，并抓住用户的第一个/最后一个订单。 （您应该直接从persons 表而不是订单加入，以避免重复，并在底部附加GROUP_BY 语句。（附sqlfiddle 显示此工作）：

SELECT
  orders.person_id,
  first_order.order_date AS min_order_date,
  last_order.order_date AS max_order_date
FROM `orders`
LEFT JOIN `orders` first_order ON (
    first_order.person_id = orders.person_id 
    AND first_order.order_date = (
        SELECT MIN(order_date)
        FROM `orders`
        WHERE person_id = orders.person_id
    )
)
LEFT JOIN `orders` last_order ON (
    last_order.person_id = orders.person_id 
    AND last_order.order_date = (
        SELECT MAX(order_date)
        FROM `orders`
        WHERE person_id = orders.person_id
    )
)
WHERE FROM_UNIXTIME(last_order.order_date) >= DATE_ADD(FROM_UNIXTIME(first_order.order_date), INTERVAL 6 MONTH)
GROUP BY person_id

Answer 2

SELECT DATE(MIN(FROM_UNIXTIME(t2.order_date))), t1.person_id 
FROM the_table t1
INNER JOIN the_table t2 ON t1.person_id=t2.person_id
AND DATE(FROM_UNIXTIME(t1.order_date)) >= DATE_ADD(DATE(FROM_UNIXTIME(t2.order_date)), INTERVAL 6 MONTH)
GROUP BY t1.person_id;