django 基于函数的通用视图迁移到基于类的视图答案

【问题标题】：django function based generic views migration to class based viewsdjango 基于函数的通用视图迁移到基于类的视图
【发布时间】：2013-03-25 08:18:08
【问题描述】：

我最近从 django 1.4 迁移到 django 1.5，我收到了这个错误

ViewDoesNotExist: Could not import django.views.generic.date_based.archive_index. Parent module django.views.generic.date_based does not exist.

谷歌搜索让我发现基于功能的视图已被贬低。我正在尝试迁移到基于类的视图，但发现它很困难。这是我的意见。py

from app.models import Season
from django.conf.urls import *
from cms.models import News, File


def get_extra_context():
    past_seasons = Season.objects.filter(in_progress = False)
    try:
        current_season = Season.objects.get(in_progress = True)
    except Season.DoesNotExist:
        current_season = None
    files = File.objects.all().order_by('-id')[:5]
    output = {
        'current_season': current_season,
        'past_seasons': past_seasons,
        'files': files,
        }
    return output

dictionary = {
    'queryset': News.objects.all(),
    'date_field': 'date',
    'extra_context': get_extra_context(),
}


urlpatterns= patterns(
    'django.views.generic.date_based',
    url(
        r'(?P<year>\d{4})/(?P<month>\w{3})/(?P<day>\d{2})/(?P<slug>[-\w]+)/$',
        'object_detail',
        dict(dictionary, slug_field = 'slug', template_name = 'cms/news/object.html'),
        name='object'
    ),
    url(
        r'^$',
        'archive_index',
        dict(dictionary, template_name = 'cms/news/list.html'),
        name='list'
    )
)

我无法将其转换为基于类的视图。任何身体都可以提供帮助。字典是我想要放入上下文的对象。

提前致谢。

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【问题讨论】：

标签： django django-views

【解决方案1】：

这就是我的做法。

urlpatterns = patterns(
    '',
    url(
        r'(?P<year>\d{4})/(?P<month>\w{3})/(?P<day>\d{2})/(?P<slug>[-\w]+)/$',
        DateDetailView.as_view(
            model = News,
            date_field = 'date',
            slug_field = 'slug',
            template_name = 'cms/news/object.html',
            #dict = dictionary,
        ),
        name='object'
    ),
)

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