获取从星期一到星期日mysql的本周所有日期

Question

我的选择查询是

SELECT DISTINCT
    CONCAT(DATE_FORMAT(CAST(call_logview.CA_N_F_Date AS DATE), "%d"),"-",DATE_FORMAT(CAST(call_logview.CA_N_F_Date AS DATE), "%b"),"-",DATE_FORMAT(CAST(call_logview.CA_N_F_Date AS DATE), "%Y")," ",DATE_FORMAT(CAST(call_logview.CA_N_F_Date AS DATE), "%a")) AS weekList,
    CAST(call_logview.CA_N_F_Date AS DATE) AS listDate 
FROM call_logview 
WHERE YEARWEEK(call_logview.CA_N_F_Date) = YEARWEEK(NOW())

这给了我下面的输出

我希望我的选择查询是从本周的星期一到星期日，如果我在 where 条件中添加“1”，即 (YEARWEEK(call_logview.CA_N_F_Date,1) = YEARWEEK(NOW(),1)) 它给了我从前一周星期日开始的结果， 但我希望结果应该是从本周的周一到周日。

Answer 1

我猜，您的 SQL 请求几乎是正确的，但是您应该将模式指定为“1”，以便 YEARWEEK(date, mode) 采用这种方式：

WHERE YEARWEEK(date, 1) = YEARWEEK(CURDATE(), 1).

所以，在你的情况下，我认为应该是这样的：

SELECT * FROM call_logview WHERE YEARWEEK(call_logview.CA_N_F_Date, 1) = YEARWEEK(NOW(), 1);