如何根据特定顺序对列表进行排序？

Question

我有两个列表： bigrams = ['apple pie', 'red vine', 'chicken salad'] bigram_info = ['red vine 1', 'apple pie 0', 'chicken salad 2']

我想根据bigrams列表订购bigram_info列表： ordered_list = ['apple pie 0', 'red vine 1', 'chicken salad 2']

我尝试了一些东西，但由于我的列表很大，我没有得到正确的结果。

``` file=open("bigrams.txt","r")
    bigrams = file.read().splitlines()
    file.close()
    #print(bigrams)
    with open("bigram_info.txt", "r") as my_file:
            for line in my_file:
               words = line.split()
               words[0 : 2] = [' '.join(words[0 : 2])]
               for w in bigrams:
                      if  w==words[0]:
                             print(line)

When I run the code it prints that elements in order of bigram_info list.Like
    ``` bigram_info = ['red vine 1', 'apple pie 0', 'chicken salad 2']```

Answer 1

如果你想按bigram中每个项目的前两个单词的位置对bigram_info进行排序，你可以这样做：

sorted(bigram_info, key=lambda x: bigrams.index(' '.join(x.split()[:2])))