支持 Python 中的逻辑门仿真程序

Question

我正在尝试在 python 中创建一个逻辑门模拟程序，以便用户可以选择他们想要模拟的逻辑门的类型。一旦选择，他们就可以输入输入，程序应该将所选逻辑门的输出值返回给用户。

这是我目前所拥有的：

print ("Logic Gate Simulation")

def AND (a,b):

    if a == 1 and b == 1:
        return 1
    else:
        return 0



def NAND (a,b):
    if a == 1 and b == 1:
        return 0
    else:
        return 1


def OR(a,b):
    if a == 1:
        return 1
    elif b == 1:
        return 1
    else:
        return 0


def NOR (a,b):
    if a != b:
        return 1
    else:
        return 1

def Main():
    question = input("what type of gate do you want to simulate - OR, AND  or NAND?  ")

    if question == 'AND':
        a = input("enter value for input 1")
        b = input("enter value for input 2")
        x= AND(a,b)
        print (x)

    else:
        print ("")
Main()

当我运行程序并输入 AND 时，输入 1 和 1 它仍然返回 0，我不明白为什么。

Answer 1

这行得通：

def AND (a,b):
    a=int(a)
    b=int(b)
    if a == 1 and b == 1:
        return 1
    else:
        return 0

你必须告诉 python a 和 b 是整数 - （有比显示的方法更好的方法）

Answer 2

这是我的代码版本（我不得不这样做作为 AS Level 的家庭作业，这可能会对你有所帮助！）：

print("Logic Gate Calculator")


def AND(a, b):  # AND Gate
    a = int(a)
    b = int(b)
    if a == 1 and b == 1:  # AND Gate logic
        return 1
    else:
        return 0


def NAND(a, b):  # NAND Gate
    a = int(a)
    b = int(b)
    if a == 1 and b == 1:  # NAND Gate logic
        return 0
    elif a == 1 and b == 0:
        return 0
    elif a == 0 and b == 1:
        return 0
    else:
        return 1


def OR(a, b):  # OR Gate
    a = int(a)
    b = int(b)
    if a == 1:  # OR Gate Logic
        return 1
    elif b == 1:
        return 1
    else:
        return 0


def NOR(a, b):  # NOR Gate
    a = int(a)
    b = int(b)
    if a == 1 and b == 0:  # NOR Gate Logic
        return 1
    elif a == 0 and b == 1:
        return 1
    elif a == 0 and b == 0:
        return 1
    else:
        return 0


def XOR(a, b):  # XOR Gate
    a = int(a)
    b = int(b)
    if a == 1 and b == 0:  # XOR Gate Logic
        return 1
    elif a == 1 and b == 1:
        return 1
    else:
        return 0


def main():  # The main program
    run = True
    while run:  # While loop
        question = input("What type of gate do you want to use OR, AND, NOR, or NAND or (Q)uit")  # Logic Gate chooser
        if question == "AND" or question == "and" or question == "And":  # If the user selects AND
            a = input("Enter value for input 1 (1 or 0):")  # Getting the Logic Gate's 1st input
            b = input("Enter value for input 2 (1 or 0):")  # Getting the Logic Gate's 2nd input
            x = AND(a, b)  # Calling the AND Function
            print("The output will be:", x)  # Output result
        elif question == "OR" or question == "or" or question == "Or":  # If the user selects OR
            a = input("Enter value for input 1 (1 or 0):")  # Getting the Logic Gate's 1st input
            b = input("Enter value for input 2 (1 or 0):")  # Getting the Logic Gate's 2nd input
            x = OR(a, b)  # Calling the OR Function
            print("The output will be:", x)  # Output result
        elif question == "NOR" or question == "nor" or question == "Nor":  # If the user selects NOR
            a = input("Enter value for input 1 (1 or 0):")  # Getting the Logic Gate's 1st input
            b = input("Enter value for input 2 (1 or 0):")  # Getting the Logic Gate's 2nd input
            x = NOR(a, b)  # Calling the NOR function
            print("The output will be:", x)  # Output result
        elif question == "NAND" or question == "nand" or question == "Nand":  # If the user selects NAND
            a = input("Enter value for input 1 (1 or 0):")  # Getting the Logic Gate's 1st input
            b = input("Enter value for input 2 (1 or 0):")  # Getting the Logic Gate's 2nd input
            x = NAND(a, b)  # Calling the NAND function
            print("The output will be:", x)  # Output result
        elif question == "XOR" or question == "xor" or question == "Xor":  # If the user selects XOR
            a = input("Enter value for input 1 (1 or 0):")  # Getting the Logic Gate's 1st input
            b = input("Enter value for input 2 (1 or 0):")  # Getting the Logic Gate's 2nd input
            x = XOR(a, b)  # Calling the XOR function
            print("The output will be:", x)  # Output result
        elif question == "Q" or question == "q":  # Quiting the program
            run = False
        else:
            print("Please enter one of the shown logic gates")  # Error handling


main()

Answer 3

a=真 b=真

输出=a 和 b 打印（输出）

a=真 b=假

输出=a 和 b 打印（输出）

请试试这个

Answer 4

它有效。采用 如果 a == 1： 如果 b == 1： 返回 1 别的 返回 0