jsgrid入门示例不起作用答案

【问题标题】：jsgrid getting started sample does not workjsgrid入门示例不起作用
【发布时间】：2018-08-07 15:49:11
【问题描述】：

对于我的一个项目，我必须使用 jsgrid (http://js-grid.com)。

为了测试是否如何使用 jsgrid，我想做一个“入门”示例 (http://js-grid.com/getting-started. 我的问题，在我看来，我按照示例所说的那样做了所有事情，但最终没有奏效。

我错过了什么？

这是我的代码：

<!DOCTYPE html>
<html>
<head>
    <link type="text/css" rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/jsgrid/1.5.3/jsgrid.min.css" />
    <link type="text/css" rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/jsgrid/1.5.3/jsgrid-theme.min.css" />
    
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
    <script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/jsgrid/1.5.3/jsgrid.min.js"></script>
    <script>
        var clients = [
            { "Name": "Otto Clay", "Age": 25, "Country": 1, "Address": "Ap #897-1459 Quam Avenue", "Married": false },
            { "Name": "Connor Johnston", "Age": 45, "Country": 2, "Address": "Ap #370-4647 Dis Av.", "Married": true },
            { "Name": "Lacey Hess", "Age": 29, "Country": 3, "Address": "Ap #365-8835 Integer St.", "Married": false },
            { "Name": "Timothy Henson", "Age": 56, "Country": 1, "Address": "911-5143 Luctus Ave", "Married": true },
            { "Name": "Ramona Benton", "Age": 32, "Country": 3, "Address": "Ap #614-689 Vehicula Street", "Married": false }
        ];
     
        var countries = [
            { Name: "", Id: 0 },
            { Name: "United States", Id: 1 },
            { Name: "Canada", Id: 2 },
            { Name: "United Kingdom", Id: 3 }
        ];
     
        $("#jsGrid").jsGrid({
            width: "100%",
            height: "400px",
     
            inserting: true,
            editing: true,
            sorting: true,
            paging: true,
     
            data: clients,
     
            fields: [
                { name: "Name", type: "text", width: 150, validate: "required" },
                { name: "Age", type: "number", width: 50 },
                { name: "Address", type: "text", width: 200 },
                { name: "Country", type: "select", items: countries, valueField: "Id", textField: "Name" },
                { name: "Married", type: "checkbox", title: "Is Married", sorting: false },
                { type: "control" }
            ]
        });
    </script>
</head>
<body>
    <div id="jsGrid"></div>
</body>
</html>

【问题讨论】：

标签： javascript grid jsgrid

【解决方案1】：

您的脚本代码在 DOM 准备好之前运行。我将您的脚本包装在两者之间：

$(document).ready(function() {

和：

});

它在显示的表格中运行良好。部分解释见here。

jsGrid 是一个很棒的工具。不幸的是，它的诊断几乎为零。有些地方可能是错误的，比如一个简单的错字，但根本没有迹象表明哪里出了问题。

【讨论】：

非常感谢，现在可以正常使用了！我没有看到它在错误的地方。