【发布时间】:2021-10-16 04:42:34
【问题描述】:
型号
class CreatorRawArtwork(models.Model):
id = models.AutoField(primary_key=True)
title = models.CharField(max_length=500)
descripton = models.TextField()
editions = models.IntegerField(null=True, blank=True)
price = models.CharField(max_length=500)
created_at = models.DateTimeField(auto_now_add=True, null=True, blank=True)
medias = models.FileField(null=True, blank=True, upload_to="raw-medias")
user = models.ForeignKey(to=Login, on_delete=models.CASCADE, related_name="creatorrawartwork", null=True, blank=True
)
collection = models.ForeignKey(
to=DesignerCollection, on_delete=models.CASCADE, related_name="creatorrawartwork", null=True, blank=True)
categories = models.ManyToManyField(DesignerCategories, related_name='creatorrawartwork')
def __str__(self):
return self.title
序列化器
class CreatorRawArtworkSerializer(serializers.ModelSerializer):
categories = serializers.PrimaryKeyRelatedField(queryset=DesignerCategories.objects.all(), many=True)
class Meta:
model = CreatorRawArtwork
fields = "__all__"
depth=1
观看次数
class CreatorRawArtworkView(viewsets.ModelViewSet):
queryset = CreatorRawArtwork.objects.all()
serializer_class = CreatorRawArtworkSerializer
在这里我正在尝试使用 drf serialier 创建 manytomany 字段,但它显示了一些错误 请检查屏幕截图中的参数和响应
请问是什么问题
【问题讨论】:
-
by
create manytomany fields,您的意思是要创建DesignerCategories对象,其值为1 和2...??或者只是想将它附加在CreatorRawArtwork对象中...?? -
[1,2] 我会发送这样的类别。因为已经创建了类别
-
您可能会以字符串的形式获取它。通过执行 json.loads()... 将其转换为列表
标签: django django-rest-framework