【发布时间】:2011-03-15 16:35:45
【问题描述】:
无论如何我可以获取整个对象平台,而不仅仅是此查询中的属性,我正在使用带有 EF4 的 Poco:
var games = (from g in ctx.Games
join p in ctx.Platforms on g.Platform.Id equals p.Id into joinTable
from j in joinTable.DefaultIfEmpty()
select new
{
GameId = g.Id,
Title = g.Title,
PlatformId = j.Id,
PlatformShort = j.Platform_short
});
我只想检索整个 Platform 对象 (j),而不是使用 PlatformId 和 PlatformShort。像“平台 = j”
还有没有更好的方法来返回一个类型化的集合而不首先迭代游戏?
foreach (var g in games)
{
Game game = new Game();
game.Platform = new Platform();
game.Id = g.GameId;
game.Title = g.Title;
game.Platform.Id = g.PlatformId;
game.Platform.Platform_short = g.PlatformShort;
col.Add(game);
}
我尝试了这个:
返回 ctx.Games.Include("平台").Take(50).ToList();
现在我得到了所有 100 条记录的相同值。
这里是 SQL:
FROM [dbo].[Games] AS [Extent1]
LEFT OUTER JOIN (SELECT [Extent2].[Id] AS [Id1], [Extent2].[Platform_short] AS [Platform_short], [Extent2].[Platform_long] AS [Platform_long], [Extent2].[Description] AS [Description], [Extent2].[Image] AS [Image], [Extent2].[CreatedDate] AS [CreatedDate1], [Extent2].[ModifiedDate] AS [ModifiedDate1]
FROM [dbo].[Platforms] AS [Extent2]
LEFT OUTER JOIN [dbo].[Games] AS [Extent3] ON [Extent2].[Id] = [Extent3].[PlatformId] ) AS [Join1] ON [Extent1].[PlatformId] = [Join1].[Id1] LEFT OUTER JOIN (SELECT [Extent4].[Id] AS [Id3], [Extent5].[Id] AS [Id2]
FROM [dbo].[Platforms] AS [Extent4]
LEFT OUTER JOIN [dbo].[Games] AS [Extent5] ON [Extent4].[Id] = [Extent5].[PlatformId] ) AS [Join3] ON [Extent1].[PlatformId] = [Join3].[Id3]
【问题讨论】:
-
您的应用程序有问题,因为使用
Platform = j应该可以工作。
标签: linq entity-framework-4 linq-to-entities poco