使用 CodeIgniter 从数据库中获取数据

Question

我需要帮助从数据库中获取数据并在视图中显示它们。 我的数据库名称是 directory 和表 usernames，其中包括：id、title、body、slug、username、platform、gender、age 和 created_at。 我使用 foreach 显示数据库中的所有帖子，但我现在想显示基于 platform 的特定帖子。 我该怎么做？

这是我用来显示数据库中按 id 排序的所有用户名的代码：

<div class="col-md-6 mb-4">
    <div class="card">

    <div class="card-body" style="height: 130px;">
      <h5 class="card-title"><?php echo $username_data['title']; ?></h5>
      <p class="card-text"><?php echo word_limiter($username_data['body'], 24); ?></p>
  </div>
    <div class="card-footer text-muted">
        <div class="row">
            <div class="col-6">
                <small>Created at: <?php echo $username_data['created_at'];?></small><br> 
          <strong>Is <?php echo $username_data['gender'];?></strong>
            </div>
            <div class="col-6 text-right">
                <a href="<?php echo site_url('usernames/' . $username_data['slug']); ?>" class="btn btn-primary text-right">View full message</a>
            </div>
        </div>
  </div>
</div>
</div>

这是我的模型：

<?php
class Usernames extends CI_Controller{
    public function index(){
        $data['title'] = 'Lastest Posts';

        $data['posts'] = $this->post_model->get_usernames();

        $this->load->view('templates/header');
        $this->load->view('usernames/index', $data);
        $this->load->view('templates/footer');
    }

    public function view($slug = NULL){ 
        $data['post'] = $this->post_model->get_usernames($slug);
        $query = $this->db->get('usernames');

        if(empty($data['post'])){
            show_404();
        }

        $data['title'] = $data['post']['title'];

        $this->load->view('templates/header');
        $this->load->view('usernames/view', $data);
        $this->load->view('templates/footer');

    }

    public function create(){
        $data['title'] = 'Create Post';

        $this->form_validation->set_rules('title','Title','required');
        $this->form_validation->set_rules('body','Message','required');
        $this->form_validation->set_rules('username','Username','required');
        $this->form_validation->set_rules('age','Age','required');
        $this->form_validation->set_rules('gender','Gender','required');
        $this->form_validation->set_rules('platform','Platform','required');

        if($this->form_validation->run() === FALSE){
            $this->load->view('templates/header');
            $this->load->view('usernames/create', $data);
            $this->load->view('templates/footer');
        } else {
            $this->post_model->create_username();
            redirect('usernames');
        }   
    }
    public function snapchat(){
        $data['title'] = 'Lastest Posts';

        $data['posts'] = $this->post_model->get_usernames();



        $this->load->view('templates/header');
        $this->load->view('usernames/snapchat', $data);
        $this->load->view('templates/footer');
    }
}

型号：

<?php
class Post_model extends CI_Model{
    public function __construct(){
        $this->load->database();
    }
    public function get_usernames($slug = FALSE){
        if($slug === FALSE){
            $this->db->order_by('usernames.id', 'DESC');
            $query = $this->db->get('usernames');
            return $query->result_array();
        }

        $query = $this->db->get_where('usernames', array('slug' => $slug));
        return $query->row_array();
    }

    public function create_username(){
        $slug_link = substr(str_replace(['+', '/', '='], '', base64_encode(random_bytes(16))), 0, 16);
        $slug = url_title($this->input->post('title').'-'.$slug_link);

        $data = array(
            'title' => $this->input->post('title'),
            'slug' => $slug,
            'body' => $this->input->post('body'),
            'platform' => $this->input->post('platform'),
            'age' => $this->input->post('age'),
            'gender' => $this->input->post('gender'),
            'username' => $this->input->post('username')
        );

        return $this->db->insert('usernames', $data);
    }
}

一切正常，但我真的不知道如何获取这些数据。 我需要在这个特定页面（'telegram.php'）中显示所有包含来自平台的 Telegram 的行。 如前所述，我的数据库结构如下：

目录（数据库名称）

用户名（表名）

->id->title->body->slug->user

Answer 1

public function get_usernames_from_platform($platform){
        if(!empty($platform)){
            $this->db->where('platform',$platform);
            $this->db->order_by('usernames.id', 'DESC');
            $query = $this->db->get('usernames');
            return $query->result_array();
        }

        return array();
    }

将方法添加到您的模型中并调用它以获取控制器中相应方法中的相应数据。

Answer 2

好像少了它的构造函数 $this->load->model('post_model');