【发布时间】:2012-09-18 14:50:02
【问题描述】:
我是初学者(PHP 和 MySQL),我的代码有问题在我的网站中,我创建了无限的类别和子类别 - 表格 - >
catid catname parentid
1 | animals | 0
2 | vegs | 0
3 | dog | 1
4 | cat | 1
5 | carrot | 2
我在 php 嵌套的 'ul' 中显示这个数据表(代码)->
<?php
mysql_select_db($db_name, $conn); // Change for your database
$query_Recordset1 = "SELECT * FROM categories";
$Recordset1 = mysql_query($query_Recordset1, $conn) or die(mysql_error()); // Change for your database
//get all rows
while ( $row = mysql_fetch_assoc($Recordset1) )
{
$menu_array[$row['catid']] = array('catname' => $row['catname'],'parentid' => $row['parentid']);
}
//recursive function that prints categories as a nested html unordered list
function generate_menu($parent)
{
$has_childs = false;
//this prevents printing 'ul' if we don't have subcategories for this category
global $menu_array;
//use global array variable instead of a local variable to lower stack memory requierment
foreach($menu_array as $key => $value)
{
if ($value['parentid'] == $parent)
{
//if this is the first child print '<ul>'
if ($has_childs === false)
{
//don't print '<ul>' multiple times
$has_childs = true;
//echo '<ul>';
echo '<ul id="categories">';
}
echo '<li><a href="category.php?catname=' . $value['catname'] . '/">' . $value['catname'] . '</a>';
echo '<input type="hidden" value="' . $value['catname'] . '" />';
generate_menu($key);
//call function again to generate nested list for subcategories belonging to this category
echo '</li>';
}
}
if ($has_childs === true) echo '</ul>';
}
//generate menu starting with parent categories (that have a 0 parent)
?>
一切都很好 显示没有问题 .... 我的问题,如果单击主类别 get me 此类别中还没有主题。 ....我需要代码来选择用户是否在主类别中选择主类别回显子类别 - 如果选择子类别,则仅在子类别中显示数据,或者如果用户在此主要类别中选择主类别回显主题 示例 :: 我有类别 Photosession 和子类别 -> photosession april - photosession Septmber - photosession Jan - photosession Feb 当我选择主类别照片时,我需要在主类别中显示所有子类别或子类别中的所有主题
-
注意 -> 我按猫名选择主题
echo '<li><a href="category.php?catname=' . $value['catname'] . '">' . $value['catname'] . '</a>';
这个我的代码来选择帖子
<?php
$categories=$_GET['catname'];
$sql = "SELECT * FROM categories WHERE catname='$categories' ";
$result = mysql_query($sql);
if(!$result){
echo '<h1>The category could not be displayed, please try again later.</h1>' . mysql_error();
}else{
if(mysql_num_rows($result) == 0){
echo '<h1>This category does not exist.</h1>';
}else{
while($row = mysql_fetch_assoc($result))
{
echo '<title>' . $row['catname'] . ' | E3rafly.com</title>';
}
?>
<?php
$categories=$_GET['catname'];
$sql = "SELECT * FROM posts WHERE categories='$categories' " or die (mysql_error());
$result = mysql_query($sql);
if(!$result){
echo '<h1>The topics could not be displayed, please try again later.</h1>';
}else{
if(mysql_num_rows($result) == 0)
{
echo '<h1>There are no topics in this category yet.</h1>';
}else{
?>
<?php
while($row = mysql_fetch_assoc($result)){
echo '
<div class="span3 block">
<div class="view view-first">
<div class="tringle"></div>
<a href="readmore.php?postid=' . $row['postid'] . '"><img src="admin/' . $row['thumbpath'] . '" title="' . $row['title'] . '" /></a>
<div class="mask">
<a href="admin/' . $row['imagepath'] . '" rel="prettyPhoto" class="info"></a>
<a href="readmore.php?postid=' . $row['postid'] . '" class="link"></a>
</div>
</div>
<div class="descr">
<h4><a href="readmore.php?postid=' . $row['postid'] . '">',substr($row['title'],0,150),' ..</a></h4>
<p>',substr($row['description'],0,200),'.</p>
<div class="meta">
<hr>
<span class="meta_comment"><i class="icon-comment"></i> <strong>Comments:</strong><ahref="blog_single_i.html">11</a></span>
<span class="meta_date"><i class="icon-calendar"></i>
<strong>Date:</strong> <a href="readmore.php?postid=' . $row['postid'] . '">' . $row['create_on'] . '</a></span>
<div class="clearfix"></div>
</div>
</div>
</div>
';
}}}}}
?>
我认为我的问题很简单,但我不知道该怎么做...我需要帮助.. !!
【问题讨论】:
-
请总结您的问题。
-
@rationalboss 谢谢你现在看看我的网站afrogfx.com/index.php 向左看你会看到类别 Tahrir Nights 和 Photo Sessions 类别编号 2 有子类别 2012 年 4 月点击 + 你会找到它 点击照片如果单击主类别向我显示子类别,并且如果单击子类别上的 clcik 向我显示子类别中的所有帖子,我将在此处获得非帖子的会话
-
@rationalboss 你懂马的问题吗??
标签: php mysql show categories