将图片发布到服务器时如何获得响应

Question

我使用此代码将图片从我的 sdcard 上传到服务器 deviantart.com。
我使用 post 方法；本服务器支持上传图片并回复图片的url：

    public int uploadFile(String sourceFileUri) {

      String fileName = sourceFileUri;

      HttpURLConnection conn = null;
      DataOutputStream dos = null;  
      String lineEnd = "\r\n";
      String twoHyphens = "--";
      String boundary = "*****";
      int bytesRead, bytesAvailable, bufferSize;
      byte[] buffer;
      int maxBufferSize = 1 * 1024 * 1024; 
      File sourceFile = new File(sourceFileUri); 

      if (!sourceFile.isFile()) {

           dialog.dismiss(); 

           Log.e("uploadFile", "Source File not exist :"
                               +uploadFilePath + "" + uploadFileName);

           runOnUiThread(new Runnable() {
               public void run() {
                   messageText.setText("Source File not exist :"
                           +uploadFilePath + "" + uploadFileName);
               }
           }); 

           return 0;

      }
      else
      {
           try { 

                 // open a URL connection to the Servlet
               FileInputStream fileInputStream = new FileInputStream(sourceFile);
               URL url = new URL(upLoadServerUri);

               // Open a HTTP  connection to  the URL
               conn = (HttpURLConnection) url.openConnection(); 
               conn.setDoInput(true); // Allow Inputs
               conn.setDoOutput(true); // Allow Outputs
               conn.setUseCaches(false); // Don't use a Cached Copy
               conn.setRequestMethod("POST");
               conn.setRequestProperty("Connection", "Keep-Alive");
               conn.setRequestProperty("ENCTYPE", "multipart/form-data");
               conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
               conn.setRequestProperty("uploaded_file", fileName); 

               dos = new DataOutputStream(conn.getOutputStream());

               dos.writeBytes(twoHyphens + boundary + lineEnd); 
               dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\""
                                         + fileName + "\"" + lineEnd);

               dos.writeBytes(lineEnd);

               // create a buffer of  maximum size
               bytesAvailable = fileInputStream.available(); 

               bufferSize = Math.min(bytesAvailable, maxBufferSize);
               buffer = new byte[bufferSize];

               // read file and write it into form...
               bytesRead = fileInputStream.read(buffer, 0, bufferSize);  

               while (bytesRead > 0) {

                 dos.write(buffer, 0, bufferSize);
                 bytesAvailable = fileInputStream.available();
                 bufferSize = Math.min(bytesAvailable, maxBufferSize);
                 bytesRead = fileInputStream.read(buffer, 0, bufferSize);   


                }

               // send multipart form data necesssary after file data...
               dos.writeBytes(lineEnd);
               dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

               // Responses from the server (code and message)

               serverResponseCode = conn.getResponseCode();
               String serverResponseMessage = conn.getResponseMessage();

               Log.i("uploadFile", "HTTP Response is : " 
                       + serverResponseMessage + ": " + serverResponseCode);

               if(serverResponseCode == 200){

                   runOnUiThread(new Runnable() {
                            public void run() {
//                              
//                              String msg = "File Upload Completed.\n\n See uploaded file here : \n\n"
//                                            +" http://www.androidexample.com/media/uploads/"
//                                            +uploadFileName;

//                              messageText.setText(msg);
                                Toast.makeText(UploadToServer.this, "File Upload Complete.", 


                         Toast.LENGTH_SHORT).show();
                        }
                    });                
               }    

               //close the streams //
               fileInputStream.close();
               dos.flush();
               dos.close();

          } catch (MalformedURLException ex) {

              dialog.dismiss();  
              ex.printStackTrace();

              runOnUiThread(new Runnable() {
                  public void run() {
                      messageText.setText("MalformedURLException Exception : check script url.");
                      Toast.makeText(UploadToServer.this, "MalformedURLException", Toast.LENGTH_SHORT).show();
                  }
              });

              Log.e("Upload file to server", "error: " + ex.getMessage(), ex);  
          } catch (Exception e) {

              dialog.dismiss();  
              e.printStackTrace();

              runOnUiThread(new Runnable() {
                  public void run() {
                      messageText.setText("Got Exception : see logcat ");
                      Toast.makeText(UploadToServer.this, "Got Exception : see logcat ", 
                              Toast.LENGTH_SHORT).show();
                  }
              });
              Log.e("Upload file to server Exception", "Exception : " 
                                               + e.getMessage(), e);  
          }
          dialog.dismiss();       
          return serverResponseCode; 

       } // End else block 
     } 

响应码 = 200。

但我想得到一个字符串响应（图片的url）；我不知道如何获得字符串响应

谢谢！

Answer 1

try 
{
       inStream = new DataInputStream ( conn.getInputStream() );
       String str;
       while (( str = inStream.readLine()) != null)
       {
            String yourmessage = str;
       }
       inStream.close();
}
catch (IOException ioex)
{
    Log.e("SD card doFile upload error: ",""+ ioex.getMessage());       
}

你应该得到字符串“yourmessage”中的返回数据

Answer 2

使用getInputStream方法获取返回的流。

try {
 InputStream in = new BufferedInputStream(conn.getInputStream());
 readStream(in); // here you can read the stream and extract your url
finally {
 conn.disconnect();
}