【发布时间】:2014-04-28 10:59:58
【问题描述】:
我正在使用 jQuery ajax 上传文件。当我点击上传按钮时,它失败并且ajax的错误部分显示Uncaught TypeError: Cannot read property 'length' of undefined。我检查了代码,发现alerting the jqXHR shows success in the first ajax call,but the ajax call in submitForm() is not working。控制器在$.each(event,data)之前停止,并在控制台中显示上述错误。请帮助我。
我的代码如下:
$(document).ready(function()
{
//for checking whether the file queue contain files or not
var files;
// Add events
$('input[type=file]').on('change', prepareUpload);
// Grab the files
function prepareUpload(event)
{
files = event.target.files;
alert(files);
}
$("#file-form").on('submit',uploadFiles);
function uploadFiles(event)
{
event.stopPropagation();
event.preventDefault();
// Create a formdata object and add the files
var data = new FormData();
$.each(files, function(key, value)
{
data.append(key, value);
//alert(key+' '+ value);
});
$.ajax({
url: 'module/portal/filesharing/upload.php?files',
type: 'POST',
data: data,
cache: false,
dataType: 'json',
processData: false,
contentType: false,
success: function(data, textStatus, jqXHR)
{
if(typeof data.error === 'undefined')
{
// Success so call function to process the form
submitForm(event, data);
}
else
{
console.log('ERRORS: ' + data.error);
}
}
});
function submitForm(event, data)
{
// Create a jQuery object
$form = $(event.target);
// Serialize the form data
var formData = $form.serialize();//controller stops here
// sterilise the file names
$.each(data.files, function(key, value)
{
formData = formData + '&filenames[]=' + value;
});
$.ajax({
url: 'update.php',
type: 'POST',
data: formData,
cache: false,
dataType: 'json',
success: function(data, textStatus, jqXHR)
{
if(typeof data.error === 'undefined')
{
// Success so call function to process the form
console.log('SUCCESS: ' + data.success);
}
else
{
// Handle errors here
console.log('ERRORS: ' + data.error);
}
},
error: function(jqXHR, textStatus, errorThrown)
{
// Handle errors here
console.log('ERRORS: ' + textStatus);
},
complete: function()
{
// STOP LOADING SPINNER
}
});
}
}
});
</script>
HTML:
<form id='file-form' action="" method="post" enctype="multipart/form-data">
<input type="file" name="file" id="filename" ><br>
<input type="submit" id='upload' value="Upload file">
</form>
我的更新.php:
$data = array();
if(isset($_GET['files']))
{
$error = false;
$files = array();
$uploaddir = 'module/portal/filesharing/upload/';
foreach($_FILES as $file)
{
if(move_uploaded_file($file['tmp_name'], $uploaddir .basename($file['name'])))
{
$files[] = $uploaddir .$file['name'];
}
else
{
$error = true;
}
}
$data = ($error) ? array('error' => 'There was an error uploading your files') : array('files' => $files);
}
else
{
$data = array('success' => 'Form was submitted', 'formData' => $_POST);
}
echo json_encode($data);
【问题讨论】:
标签: php jquery file-upload