无法使用 PHP 将多个文件上传到文件夹

Question

我需要一些帮助。我需要使用 PHP 将多个文件上传到文件夹中。在这里我只能上传单个文件。我在下面解释我的代码。

 <input style="padding:0;" type="file" class="filestyle form-control" data-size="lg" name="bannerimage" id="bannerimage">
<input style="padding:0;" type="file" class="filestyle form-control" data-size="lg" name="bannerimage1" id="bannerimage1">

这是我的 PHP 代码。

<?php
 $imageName='bannerimage';
 $imagePath="uploads/";
 if ($_FILES['bannerimage']['name'] != ""){
    uploadImage($_FILES,$imageName,$imagePath,function($image){
       $newCustomerobj->image =$image['img'];
    }
 }
  public function uploadImage($files, $imageFieldName, $imageDirPath, $callback) {
        $result = array();
        //  print_r( $_FILES);exit;
        $imageName = generateRandomNumber() . '_' . $_FILES[$imageFieldName]['name'];
        // echo($_FILES[$imageFieldName]['tmp_name']);exit;
        $target_dir = $imageDirPath;
        $target_file = $target_dir . basename($imageName);
        $uploadOk = 1;
        $imageFileType = pathinfo($target_file, PATHINFO_EXTENSION);
        if (file_exists($target_file)) {
            $result['msg'] = "Sorry, file already exists.";
            $result['num'] = 0;
            $callback($result);
            $uploadOk = 0;
        }
        if ($_FILES[$imageFieldName]["size"] > 500000) {
            //  echo 'fileSize';exit;
            $result['msg'] = "Sorry, file size is large.";
            $result['num'] = 0;
            $callback($result);
            $uploadOk = 0;
        }
        if (($imageFileType != "jpg" && $imageFileType != "JPG") && $imageFileType != "png" && $imageFileType != "jpeg" && $imageFileType != "gif") {
            $result['msg'] = "Sorry, only .jpg,.jpeg,.gif and .png files are allowed.";
            $result['num'] = 0;
            $callback($result);
            $uploadOk = 0;
        }
        if ($uploadOk == 0) {
            $result['msg'] = "Sorry, Your file could not uploaded.";
            $result['num'] = 0;
            $callback($result);
        } else {
            if (move_uploaded_file($_FILES[$imageFieldName]['tmp_name'], $target_file)) {
                $result['msg'] = "Image has uploaded successfully.";
                $result['num'] = 1;
                $result['img'] = $imageName;
                $callback($result);
            } else {
                $result['msg'] = "Sorry, Your Image could not uploaded to the directory.";
                $result['num'] = 0;
                $callback($result);
            }
        }
    }
?>

这里我只能添加一张图片，但这里我需要上传多张图片。请帮我解决这个问题。

Answer 1

使用multiple attr

multiple 属性是一个布尔属性。

如果存在，它指定可以一次选择多个选项。

HTML 输入

<input style="padding:0;" type="file" class="filestyle form-control" data-size="lg" multiple name="bannerimage[]" id="bannerimage">

你的 PHP

 // set all images into array
function reArrayFiles(&$file_post)
{

    $file_ary = array();
    $file_count = count($file_post['name']);
    $file_keys = array_keys($file_post);

    for ($i = 0; $i < $file_count; $i++) {
        foreach ($file_keys as $key) {
            $file_ary[$i][$key] = $file_post[$key][$i];
        }
    }

    return $file_ary;
}


if ($_FILES['bannerimage']['name'] != "") {
    $file_ary = reArrayFiles($_FILES['bannerimage']);
    foreach ($file_ary as $file) {
        uploadImage($file, $imageName, $imagePath, function ($image) {
            $newCustomerobj->image = $image['img'];
        }
    }
}

更新

上传两张单独的图片

<input style="padding:0;" type="file" class="filestyle form-control" data-size="lg" name="bannerimage" id="bannerimage">
<input style="padding:0;" type="file" class="filestyle form-control" data-size="lg" name="bannerimage1" id="bannerimage1">

PHP

$imageName = 'bannerimage';
$imageName2 = 'bannerimage1'; // for bannerimage1
$imagePath = "uploads/";

// uploading bannerimage
if ($_FILES['bannerimage']['name'] != "") {
    uploadImage($_FILES, $imageName, $imagePath, function ($image) {
        $newCustomerobj->image = $image['img'];
    }
 }

 // uploading bannerimage1
if ($_FILES['bannerimage1']['name'] != "") {
    uploadImage($_FILES, $imageName2, $imagePath, function ($image) {
        $newCustomerobj->image = $image['img'];
    }
 }