如何将我的搜索结果转换为 php 中的链接？ [关闭]

Question

我的搜索运行良好，但我需要将每个结果链接到描述页面。关于如何做的任何想法？

<?php
session_start();

require_once 'login.php';

$conn = mysqli_connect($server,$user,$password,$dbase);
    if(!$conn){
        die("Failure to connect".mysqli_connect_error());               
    }
    $id = $_SESSION['twitcher'];
    $srch = $_POST['searchstr'];
    $sql = "select * from gallery where title like '%$srch%'";
    $result = mysqli_query($conn,$sql); 

    if(mysqli_num_rows($result) > 0){
       while ($rows=mysqli_fetch_assoc($result)){
            echo $rows['title'].$br.$br;
        }       
    }else echo "No posts found.";
    mysqli_close($conn);        

?>

Answer 1

与@Dagon stated 完全相同：您只需简单地回显一个链接标签 (<a>)

while ($rows=mysqli_fetch_assoc($result)) {
    echo "<a href='/link_to_where_you_want_to_go'>" . $rows['title'] . "</a>" . $br . $br;
}