在Java中的数组中查找多个搜索结果

Question

我有一个由名字组成的数组。我有一个搜索功能，可以搜索数组的元素，它工作正常。但是，对于数组的多个元素，我不知道如何打印返回了多少结果。例如，如果在我的示例中找到“John”，我不知道如何表明找到了多个结果。有人请帮助我。对于找到的每个结果，我需要获得“计数”以增加 1 倍。这是我的代码： `

import java.util.*;

class Search {
    public static void main(String[] args) {

    Scanner search = new Scanner(System.in); 
       String[] firstName = new String[]{"John", "Thomas", "Samuel", "Chris", "Daniel", "Joey", "David", "Joshua", "Michael", "John"};
       Arrays.sort(firstName);
       System.out.print("Enter a search term: ");
       String name = search.next();

       int i;

       boolean foundIt = false;

    search:
       for (i = 0; i < firstName.length; i++) {
           if (firstName[i] == name) {
                   foundIt = true;

               }
           }


       if (foundIt = true){
            System.out.println("Your search term of " + name + " produced " + count + " search results");
       }

       else {
           System.out.println("Your search term of " + name + " did not return any results");
       }
   }
}

Answer 1

您可以将 boolean foundIt 更改为 int count，并在将 foundIt 设置为 true 的位置递增。

比如：

int count = 0;

search:
   for (i = 0; i < firstName.length; i++) {
       if (firstName[i] == name) {
               count++;
       }
   }


   if (count > 0){
        System.out.println("Your search term of " + name + " produced " + count + " search results");
   }

   else {
       System.out.println("Your search term of " + name + " did not return any results");
   }

Answer 2

试试这个代码：

    Scanner search = new Scanner(System.in);
    String[] firstName = {"John", "Thomas", "Samuel", "Chris", "Daniel", "Joey", "David", "Joshua", "Michael", "John"};
    Arrays.sort(firstName);
    System.out.print("Enter a search term: ");
    String name = search.next();

    int count = 0;
    for (String aFirstName : firstName) {
        if (aFirstName.equals(name)) {
            count++;
        }else if(count > 0){
            break;
        }
    }

    if(count > 0){
        System.out.println("Your search term of " + name + " produced " + count + " search results");
    }else{
        System.out.println("Your search term of " + name + " did not return any results");
    }

Answer 3

您可以将结果添加到 ArrayList，这样更容易理解。此外，您在 if 语句中分配变量并在字符串上使用 == 运算符，您应该使用 .equals()。

另一个突出的是代码中的标签，你应该远离它们，因为它们需要使用臭名昭著的break 语句。见 Dijkstra 的considered harmful.

这样您之后还可以遍历找到的名称。

看例子：

import java.util.ArrayList;
import java.util.Arrays;    
import java.util.List;
import java.util.Scanner;


class Search {
    public static void main(String[] args) {

        Scanner search = new Scanner(System.in);
        String[] firstNames = new String[]{
            "John",
            "Thomas",
            "Samuel",
            "Chris",
            "Daniel",
            "Joey",
            "David",
            "Joshua",
            "Michael",
            "John"};

        Arrays.sort(firstNames);
        System.out.print("Enter a search term: ");
        String name = search.next();

        List<String> results = new ArrayList<String>();
        for (String s : firstNames) {
            if (s.equals(name)) {
                results.add(s);
            }
        }


        if (results.size() > 0) {
            System.out.println("Your search term of " + name + " produced " + results.size() + " search results");
        } else {
            System.out.println("Your search term of " + name + " did not return any results");
        }
    }
}

Answer 4

private void searchName(){

Employee[]e=toEmployee();
for(int i=0;i<em.size();i++){
    if(e[i].getName().equals(tfs.getText())){
        tfi.setText(e[i].getId());
        tfn.setText(e[i].getName());
        tfh.setText(e[i].getHour()+"");
        tfr.setText(e[i].getRate()+"");
    }
}
}