【发布时间】:2018-09-18 06:35:25
【问题描述】:
我正在尝试根据两个相关核心的条件查询一个核心,但我没有得到任何结果。每个单独的连接都可以正常工作。
我应该如何表达一个基于两个核心加入的查询?
在 SQL 世界中,这被称为三张表的内连接以获得交集。
SQL 对应:
SELECT *
FROM proddev
INNER JOIN department ON HMProductDevelopmentDepartment==id
INNER JOIN season ON HMProductDevelopmentSeason==id
我正在运行 solr-7.3.1。查询在http://localhost:8983/solr/#/proddev/query中执行
{!join from=id fromIndex=season to=HMProductDevelopmentSeason}name:"8-2018" AND _query_ {!join from=id fromIndex=department to=HMProductDevelopmentDepartment}DepartmentNumber:6515
主表:proddev
{
"id":"48352.32064.2208.65165",
"name":["0439370D"],
"HMProductDevelopmentDepartment":["48352.32064.61248.42035"],
"HMProductDevelopmentSeason":["48352.32064.24988.33959"],
"HMCandidateForFileSync":[" FALSE "],
"PublishedDate":[" 11/14/2017 11:29:25 AM "],
...
}
相关核心:季节
{
"id":"48352.32064.24988.33959",
"name":["8-2018"],
"_version_":1611866808030068736,
"name_str":["8-2018"]}]
}
相关核心:部门
{
"id":"48352.32064.61248.42035",
"name":["448"],
"DepartmentNumber":[" 6515"],
"_version_":1611923411375751168,
"name_str":["448"],
"DepartmentNumber_str":[" 6515"]}]
}
调试响应:
"responseHeader":{
"status":0,
"QTime":1,
"params":{
"q":"{!join from=id fromIndex=season to=HMProductDevelopmentSeason}name:\"8-2018\" AND _query_ {!join from=id fromIndex=department to=HMProductDevelopmentDepartment}DepartmentNumber:6515",
"debugQuery":"on",
"_":"1537194871447"}},
"response":{"numFound":0,"start":0,"docs":[]
},
"debug":{
"rawquerystring":"{!join from=id fromIndex=season to=HMProductDevelopmentSeason}name:\"8-2018\" AND _query_ {!join from=id fromIndex=department to=HMProductDevelopmentDepartment}DepartmentNumber:6515",
"querystring":"{!join from=id fromIndex=season to=HMProductDevelopmentSeason}name:\"8-2018\" AND _query_ {!join from=id fromIndex=department to=HMProductDevelopmentDepartment}DepartmentNumber:6515",
"parsedquery":"JoinQuery({!join from=id to=HMProductDevelopmentSeason fromIndex=season}+name:\"8 2018\" +_text_:_query_ {!join from=id to=HMProductDevelopmentDepartment fromIndex=department}DepartmentNumber:6515)",
"parsedquery_toString":"{!join from=id to=HMProductDevelopmentSeason fromIndex=season}+name:\"8 2018\" +_text_:_query_ {!join from=id to=HMProductDevelopmentDepartment fromIndex=department}DepartmentNumber:6515",
"explain":{},
【问题讨论】: