检查数组中的部分匹配

Question

我有一个 JavaScript 数组，其中包含一些在请求创建用户帐户时无法使用的单词。

我正在尝试遍历请求的帐户并根据单词过滤器检查它们。如果它们包含任何单词，则该值将移动到“无效帐户”数组中。

// Create our arrays
var blacklist = ["admin", "webform", "spoof"];
var newAccounts = ["admin1@google.com", "interweb@google.com", "puppy@google.com"];
var invalidAccounts = [];

// I need to check if any of the new accounts have matches to those in the blacklist. 
// admin1@google.com would need to be pushed into the invalidAccounts array because it 
// contains the word admin. Although interweb contains the word web, it does not contain 
// the full word, webform, so should be ignored.

// Loop over the blacklist array
for(var x = 0; x < blacklist.length; x++){
  if(blacklist[x].indexOf(newAccounts) > -1){
    alert(blacklist[x] + " is in the blacklist array");
    // Push the newAccounts value into the invalidAccounts array since it contains
    // a blacklist word.
  } else {
    alert('no matches');
  }
}

我需要在上面的代码中进行哪些更改以使其与上述部分字符串匹配？

上述代码的小提琴：https://jsfiddle.net/1qwze81o/

Answer 1

您可能不需要使用所有这些，但它应该会有所帮助：

var blacklist = ["admin", "webform", "spoof"];
var newAccounts = ["admin1@google.com", "interweb@google.com", "puppy@google.com"];
var invalidAccounts = [];

// transform each email address to an object of the form:
// { email: string, valid: boolean }
var accountObjects = newAccounts.map(function (a) {
    return { email: a, valid: true };
});

// loop over each account
accountObjects.forEach(function (account) {
    // loop over the blacklisted terms
    blacklist.forEach(function (blacklisted) {
        // check to see if your account email address contains a black listed term
        // and set the valid property accordingly
        account.valid = account.email.search(blacklisted) === -1;
    });
});

// filter accountObjects, validAccounts will now contain an array of valid objects
var validAccounts = accountObjects.filter(function (a) {
    return a.valid;
});

// back to the original type of a string array
var validEmailAddresses = validAccounts.map(function (a) {
    return a.email;
});

Answer 2

使用javascript数组原生函数的解决方案：

var invalidAccounts = newAccounts.filter(function(account){ // we need to filter accounts
  return blacklist.some(function(word){ // and return those that have any of the words in the text
      return account.indexOf(word) != -1
  })
});

更多信息：Array.filter 和 Array.some

Answer 3

我们需要两个循环来实现这一点： 如下所示：

   // Loop over the blacklist array
  for(var j = 0; x < newAccounts.length; j++){
    for(var x = 0; x < blacklist.length; x++){
    if(newAccounts[j].indexOf(blacklist[x]) > -1){
        alert(blacklist[x] + " is in the blacklist array");
        // Push the newAccounts value into the invalidAccounts array since it contains a blacklist word.
      }else{
        alert('no matches');
      }
    }
    }

Answer 4

我修复了一些东西......

for (var x = 0; x < newAccounts.length; x++) // loop through new accounts
{
    // for every account check if there is any match in blacklist array
    for (var y = 0; y < blacklist.length; y++) 
    {
      // if there is match do something 
      if (newAccounts[x].indexOf(blacklist[y]) > -1)
      {
          alert(newAccounts[x] + " is in the blacklist array");
          break;
      }
  }

}

Answer 5

这是小提琴： https://jsfiddle.net/swaprks/n1rkfuzh/

JAVASCRIPT：

// Create our arrays
var blacklist = ["admin", "webform", "spoof"];
var newAccounts = ["admin1@google.com", "interweb@google.com", "puppy@google.com"];
var invalidAccounts = [];

for(var x = 0; x < newAccounts.length; x++){
    for(var y = 0; y < blacklist.length; y++){


          if( newAccounts[x].indexOf(blacklist[y]) > -1){
            alert(blacklist[x] + " is in the blacklist array");
            // Push the newAccounts value into the invalidAccounts array since it contains
            // a blacklist word.
            invalidAccounts.push(newAccounts[x]);
          }else{
            alert('no matches');
          }
    }
}