VB.Net Web 应用程序如何在 GridView 上的列下方添加列

Question

如何在另一列下添加一列，以便在进行查询输出时在同一行中有两个输出值？在我的情况下，我想显示 Emp ID 并且在该列下我想显示 Cust ID，以便 GridView 表看起来像这样

Emp ID, Rgst ID, Line #, Disc CD, Auth Emp ID, Orig Prc, Disc Amt, Disc Pct, GL Acc ID

客户 ID

另一个问题是我如何在“Orig Prc”输出的末尾添加一列或标题作为总计并将所有“Orig Prc”总和，以便它可以在与“Orig”相同的列中输出结果中华人民共和国”？所以它可能看起来像这样：

原中华人民共和国

原始 prc 输出

总计

输出是所有原始 prc 输出的总和

这可以用当前方法完成，还是我改变了在 ViewGrid 上输出数据的方法？

这是我当前的代码：

Protected Sub ExecuteButton_Click(sender As Object, e As EventArgs) Handles ExecuteButton.Click
    Dim StoreID As Integer
    Dim TransID As Integer
    Dim RgstID As Integer
    Dim dt As DataTable

    If Not Integer.TryParse(StoreIDTextbox.Text, StoreID) Then
        MsgBox("Invalid input. Please enter both Store ID and Transaction ID.")
        Exit Sub
    End If

    If Not Integer.TryParse(TransactionIDTextbox.Text, TransID) Then
        MsgBox("Invalid input. Please enter both Store ID and Transaction ID.")
        Exit Sub
    End If

    Sql.AddParam("@Str_ID", StoreID)
    Sql.AddParam("@Tran_ID", TransID)

    'Rgst_ID Validation
    If RegisterIDTextbox.Text.Length = 0 Then
        SQL.AddParam("@Rgst_ID", "")
    ElseIf RegisterIDTextbox.Text.Length > 0 Then
        RgstID = Integer.Parse(RegisterIDTextbox.Text)
        Sql.AddParam("@Rgst_ID", RgstID)
    End If

    Try
        dt = SQL.ExecQuery("Select H.Emp_ID, H.Cust_ID, H.Rgst_ID, D.TRAN_LN_NUM, D.DISC_CD, D.AUTH_EMP_ID, D.ORIG_PRC, D.DISC_AMT, D.DISC_PCT, D.GL_ACCT_ID 
                             From Transaction_Header H 
                             INNER Join LN_Detail L On (H.Str_ID = L.Str_ID And H.Rgst_ID = L.Rgst_ID And H.Tran_ID = L.Tran_ID)
                             INNER Join LN_Discount D ON (L.Str_ID = D.Str_ID And L.Rgst_ID = D.Rgst_ID And L.Tran_ID = D.Tran_ID And L.Tran_LN_Num = D.Tran_LN_Num)  
                             WHERE(H.Str_ID = @Str_ID)
                                And (H.Tran_ID = @Tran_ID)
                                And ((H.Rgst_ID = @Rgst_ID) Or (@Rgst_ID Is NULL Or @Rgst_ID = ''))")

    Catch ex As Exception
        MsgBox(ex.Message)
        Exit Sub
    End Try

    GridView2.DataSource = dt
    GridView2.DataBind()

    TimeLabel.Text = DateAndTime.Now

网格视图

<asp:GridView ID="GridView2" runat="server" AutoGenerateColumns ="False" CellPadding="4" ForeColor="#333333">
                        <AlternatingRowStyle BackColor="White" />
                        <Columns>
                            <asp:BoundField DataField="Emp_ID" HeaderText="Emp ID" /> 
                            <asp:BoundField DataField="Cust_ID" HeaderText="Cust ID" />
                            <asp:BoundField DataField="Rgst_ID" HeaderText="Rgst ID" />
                            <asp:BoundField DataField="TRAN_LN_NUM" HeaderText="Line #" />
                            <asp:BoundField DataField="DISC_CD" HeaderText="Disc CD" />
                            <asp:BoundField DataField="AUTH_EMP_ID" HeaderText="Auth Emp ID" />
                            <asp:BoundField DataField="ORIG_PRC" HeaderText="Orig Prc" />
                            <asp:BoundField DataField="Disc_Amt" HeaderText="Disc Amt" />
                            <asp:BoundField DataField="Disc_Pct" HeaderText="Disc Pct" />
                            <asp:BoundField DataField="GL_ACCT_ID" HeaderText="GL Acct ID" />
                        </Columns>

Answer 1

在您的 GridView 标记中改用 TemplateColumns，这将为您提供所需的灵活性，例如

             <asp:TemplateColumn>
           <HeaderTemplate>
              <b> Tax </b>
           </HeaderTemplate>
           <ItemTemplate>
              <asp:Label
                   Text='<%# DataBinder.Eval(Container.DataItem, "Tax") %>'
                   runat="server"/>
           </ItemTemplate>
           <EditItemTemplate>
              <asp:CheckBox
                   Text="Taxable" 
                   runat="server"/>
           </EditItemTemplate>
           <FooterTemplate>
              <asp:HyperLink id="HyperLink1"
                   Text="Microsoft"
                   NavigateUrl="http://www.microsoft.com"
                   runat="server"/>
           </FooterTemplate>
        </asp:TemplateColumn>

https://docs.microsoft.com/en-us/dotnet/api/system.web.ui.webcontrols.templatecolumn?view=netframework-4.8