将 URL 映射到我的 Java Servlet 时遇到问题

Question

我需要通过以下模式在浏览器中输入 URL 来从数据库中获取对象：

https://host.com/<something>?action=<actionName>&object=<node|interface>&selection=<list>&tenants=<list>

其中“某物”是检索参数的方法，其中参数包括：操作、对象、选择和租户。

我将如何在 web.xml 文件中建立模式以符合理解上述每个元素的方法？

  <servlet>
    <servlet-name>NewDynamicWebProject</servlet-name>
    <servlet-class>com.test.package.NewDynamicWebProject</servlet-class>
  </servlet>

  <servlet-mapping>
    <servlet-name>NewDynamicWebProject</servlet-name>
    <url-pattern>/something/*</url-pattern>
  </servlet-mapping>

我的班级：

@SuppressWarnings("serial")
public class NewDynamicWebProject extends HttpServlet {

    @Override
    protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {

        something(req, resp);

    }

    protected void something(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {

        String actionName = req.getParameter("action");
        PrintWriter out = resp.getWriter();
        out.print("<div>" + actionName + "</div>");

    }

}

如何确保我传递到我的 URL 的参数在我的“某事”方法的范围内有意义？

Answer 1

我放弃了“某事”类，只是做了以下事情：

@Override
protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {

    String actionName = req.getParameter("action");
    String objectType = req.getParameter("object");
    String selectionList = req.getParameter("selection");
    String tenantsList = req.getParameter("tenants");

    PrintWriter out = resp.getWriter();
    out.print("<div>" + actionName + " " + objectType + " " + selectionList + " " + tenantsList + "</div>");

}