【发布时间】:2014-06-25 19:48:57
【问题描述】:
我在我的 Django 应用程序中创建了一个自定义用户对象,但无法控制用户权限。我相信这是因为用户链接没有出现在 Django 管理站点的 Auth 部分中,通常控制权限。
为什么不显示?
这是来自我的 models.py 文件:
from django.contrib.auth.models import AbstractBaseUser, BaseUserManager, PermissionsMixin
from django.db import models
class UserManager(BaseUserManager):
def create_user(self, username, password=None):
"""
Creates and saves a user with the given username.
"""
user = self.model()
user.username = username
user.set_password(password)
user.save(using=self._db)
return user
def create_superuser(self, username, password):
"""
Creates and saves a superuser with the given username.
"""
user = self.create_user(username, password=password)
user.is_admin = True
user.is_staff = True
user.is_superuser = True
user.save(using=self._db)
return user
class FooUser(AbstractBaseUser, PermissionsMixin):
username = models.CharField(max_length=40, unique=True, db_index=True)
is_active = models.BooleanField(default=True)
is_admin = models.BooleanField(default=False)
is_staff = models.BooleanField(default=False)
my_time_field = models.DateTimeField(null=True, blank=True)
USERNAME_FIELD = 'username'
objects = UserManager()
class Meta:
app_label = 'foo'
def get_full_name(self):
return self.username
def get_short_name(self):
return self.username
def has_perm(self, perm, obj=None):
return self.is_admin
def has_module_perms(self, app_label):
return self.is_admin
在其他应用中,我会根据需要进一步扩展用户模型:
class CocoUser(FooUser):
mobile_number = models.CharField(max_length=64, blank=True, null=True)
first_name = models.CharField(max_length=128, blank=True, null=True)
last_name = models.CharField(max_length=128, blank=True, null=True)
email = models.CharField(max_length=128, blank=True, null=True)
这是来自我的 settings.py 文件:
MIDDLEWARE_CLASSES = (
'django.middleware.common.CommonMiddleware',
'django.contrib.sessions.middleware.SessionMiddleware',
'django.middleware.csrf.CsrfViewMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'kohlab.force_logout.ForceLogoutMiddleware',
'django.contrib.messages.middleware.MessageMiddleware',
)
INSTALLED_APPS = (
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.sites',
'django.contrib.messages',
'django.contrib.staticfiles',
'django.contrib.admin',
'django.contrib.admindocs',
'django.contrib.humanize',
'django.contrib.messages',
'django_cleanup',
'south',
'myapp',
)
TEMPLATE_CONTEXT_PROCESSORS = (
"django.contrib.auth.context_processors.auth",
"django.contrib.messages.context_processors.messages",
"django.core.context_processors.static",
"kohlab.context_processors.site",
)
AUTHENTICATION_BACKENDS = (
'django.contrib.auth.backends.ModelBackend',
)
AUTH_USER_MODEL = ‘myapp.FooUser’
这是来自我的 urls.py 文件:
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
url(r'^admin/doc/', include('django.contrib.admindocs.urls')),
url(r'^admin/', include(admin.site.urls)),
)
这是来自我的 admin.py 文件:
from django import forms
from django.contrib import admin
from django.contrib.auth.admin import UserAdmin
from coco.models import CocoUser
class CocoUserCreationForm(forms.ModelForm):
"""A form for creating new users. Includes all the required fields, plus a repeated password."""
class Meta:
model = CocoUser
fields = ('mobile_number', 'email', 'first_name', 'last_name',)
class CocoUserChangeForm(forms.ModelForm):
"""
A form for updating users. Includes all the fields on the user, but replaces the password field with the initial one.
"""
class Meta:
model = CocoUser
fields = ['is_admin', 'is_staff', 'mobile_number', 'first_name', 'last_name', 'email']
def clean_password(self):
# Regardless of what the user provides, return the initial value.
# This is done here, rather than on the field, because the field does not have access to the initial value
return self.initial["password"]
class CocoUserAdmin(UserAdmin):
# The forms to add and change user instances
form = CocoUserChangeForm
add_form = CocoUserCreationForm
# The fields to be used in displaying the CocoUser model.
# These override the definitions on the base UserAdmin that reference specific fields on auth.User.
list_display = ('id', 'first_name', 'last_name', 'email', 'mobile_number', 'is_admin', 'is_staff',)
list_filter = ('is_admin',)
fieldsets = (
(None, {'fields': ('is_admin', 'is_staff', 'mobile_number', 'first_name', 'last_name', 'email',)}),
)
add_fieldsets = (
(None, {
'classes': ('wide',),
'fields': ('mobile_number', 'email', 'first_name', 'last_name',)}
),
)
search_fields = ('id', 'mobile_number', 'email', 'first_name', 'last_name',)
ordering = ('last_name', 'first_name',)
filter_horizontal = ()
# Now register the new UserAdmin...
admin.site.register(CocoUser, CocoUserAdmin)
【问题讨论】:
-
尝试子类化
AbstractUser而不是AbstractBaseUser -
@Ngenator 我刚刚尝试转换为 AbstractUser 并最终遇到了同样的问题。用户链接不显示,我无法告知更改用户的权限。