电子邮件 Python 脚本输出

Question

我刚刚完成了我的第一个新闻网页抓取脚本，我对它非常满意，即使代码看起来一点也不好看。我想知道当我运行它时，我应该如何通过电子邮件（gmail 地址）将脚本的输出发送给自己。我试图运行 smtplib，但它对我不起作用。

这是我当前的代码：

from urllib.request import urlopen as uReq
from bs4 import BeautifulSoup as soup
from datetime import date
from dateutil import parser
import smtplib
from email.mime.text import MIMEText

my_url1 = "https://www.coindesk.com/category/business-news/legal"
my_url2 = "https://cointelegraph.com/tags/bitcoin-regulation"
my_url3 = "https://techcrunch.com/tag/blockchain/"

# Opening up the website, grabbing the page
uFeedOne = uReq(my_url1, timeout=5)
page_one = uFeedOne.read()
uFeedOne.close()

# html parser
page_soup1 = soup(page_one, "html.parser")

# grabs each publication block
containers_one = page_soup1.findAll("a", {"class": "stream-article"} )

for container_one in containers_one:
  ## get todays date.
  ## I have taken an offset as the site has older articles than today.
  today = date.today().strftime("%Y, %m, %d")

  ## The actual datetime string is in the datetime attribute of the time tag.
  date_time1 = container_one.time['datetime']

  ## The dateutil package parses the ISO-formatted date and returns a condensed version.
  date1 = parser.parse(date_time1)
  dt1 = date1.strftime("%Y, %m, %d")

  ## Simple comparison
  if dt1 == today:
      link1 = container_one.attrs['href']
      publication_date1 = "published on " + container_one.time.text
      title1 = container_one.h3.text
      description1 = "(CoinDesk)-- " +  container_one.p.text

      print("link: " + link1)
      print("publication_date: " + publication_date1)
      print("title: ", title1)
      print("description: " + description1 + " \n")


uFeedTwo = uReq(my_url2, timeout=5)
page_two = uFeedTwo.read()
uFeedTwo.close()

page_soup2 = soup(page_two, "html.parser")

containers_two = page_soup2.findAll("div",{"class": "post-preview-item-inline__content"})

for container_two in containers_two:
  today = date.today().strftime("%Y, %m, %d")

  date_time2 = container_two.time['datetime']
  date2 = parser.parse(date_time2)
  dt2 = date2.strftime("%Y, %m, %d")

  title_container2 = container_two.find("span",{"class": "post-preview-item-inline__title"})
  description_container2 = container_two.find("p",{"class": "post-preview-item-inline__text"}).text

  if dt2 == today:
    link2 = container_two.div.a.attrs['href']
    publication_date2 = "published on " + date2.strftime("%b %d, %Y")
    title2 = title_container2.text
    description2 = "(CoinTelegraph)-- " + description_container2

    print("link: " + link2)
    print("publication_date: " + publication_date2)
    print("title: ", title1)
    print("description: " + description2 + " \n")


uFeedThree = uReq(my_url3, timeout=5)
page_three = uFeedThree.read()
uFeedThree.close()

# html parser
page_soup3 = soup(page_three, "html.parser")

# grabs each publication block
containers_three = page_soup3.findAll("div",{"class": "post-block post-block--image post-block--unread"})

for container_three in containers_three:
  today = date.today().strftime("%Y, %m, %d")
  date_time3 = container_three.time['datetime']

  date3 = parser.parse(date_time3)
  dt3 = date3.strftime("%Y, %m, %d")

  keyword1 = "law"
  keyword2 = "legal"
  description_container3 = container_three.find("div", {"class": "post-block__content"}).text.strip()

  if dt3 == today and (keyword2 in description_container3) or (keyword1 in description_container3):
      link3 = container_three.header.h2.a.attrs['href']
      publication_date3 = "published on " +  date3.strftime("%b %d, %Y")
      title3 = container_three.header.h2.a.text.strip()
      description3 = "(TechCrunch)-- " + description_container3

      print("link: " + link3)
      print("publication_date: " + publication_date3)
      print("title: ", title3)
      print("description: " + description3 + " \n")

我知道我想对此做一个变体：

# Open a plain text file for reading.  For this example, assume that
# the text file contains only ASCII characters.
with open(textfile) as fp:
    # Create a text/plain message
    msg = MIMEText(fp.read())

# me == the sender's email address
# you == the recipient's email address
msg['Subject'] = 'The contents of %s' % textfile
msg['From'] = me
msg['To'] = you

# Send the message via our own SMTP server.
s = smtplib.SMTP('localhost')
s.send_message(msg)
s.quit()

Answer 1

这是使用 SMTP 向任何人发送邮件的代码 sn-p。

下面的代码是为 gmail SMT P 配置的。如果你有其他的可以 进行配置。

import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText

msg = MIMEMultipart()
msg['From'] = 'me@gmail.com'
msg['To'] = 'you@gmail.com'
msg['Subject'] = 'Enter subjecy of msg here'
message = 'here is the email'
msg.attach(MIMEText(message))

# GMAIL_SMTP_HOST = 'smtp.gmail.com'
# GMAIL_SMTP_PORT = '587'
mailserver = smtplib.SMTP('smtp.gmail.com',587)
# secure our email with tls encryption
mailserver.starttls()
mailserver.sendmail('me@gmail.com','you@gmail.com',msg.as_string())
mailserver.quit()