urlopen 在 Python 2.7 中工作，但在 Python 3.4 中失败答案

【问题标题】：urlopen works in Python 2.7 but fails in Python 3.4urlopen 在 Python 2.7 中工作，但在 Python 3.4 中失败
【发布时间】：2016-06-08 18:32:12
【问题描述】：

我的计算机上同时运行 Python 2.7.10 和 Python 3.4.4。以下代码适用于 Python 2.7.10：

import urllib2
print urllib2.urlopen('http://google.com').read()

但是，如果我继续使用 Python 3.4.4 并运行

import urllib.request
print(urllib.request.urlopen('http://google.com').read())

我得到一对很长的错误：

Traceback (most recent call last):
  File "C:\Python34\lib\urllib\request.py", line 1183, in do_open
    h.request(req.get_method(), req.selector, req.data, headers)
  File "C:\Python34\lib\http\client.py", line 1137, in request
    self._send_request(method, url, body, headers)
  File "C:\Python34\lib\http\client.py", line 1182, in _send_request
    self.endheaders(body)
  File "C:\Python34\lib\http\client.py", line 1133, in endheaders
    self._send_output(message_body)
  File "C:\Python34\lib\http\client.py", line 963, in _send_output
    self.send(msg)
  File "C:\Python34\lib\http\client.py", line 898, in send
    self.connect()
  File "C:\Python34\lib\http\client.py", line 871, in connect
    self.timeout, self.source_address)
  File "C:\Python34\lib\socket.py", line 516, in create_connection
    raise err
  File "C:\Python34\lib\socket.py", line 507, in create_connection
    sock.connect(sa)
TimeoutError: [WinError 10060] A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "<pyshell#17>", line 1, in <module>
    print(urllib.request.urlopen('http://google.com').read())
  File "C:\Python34\lib\urllib\request.py", line 161, in urlopen
    return opener.open(url, data, timeout)
  File "C:\Python34\lib\urllib\request.py", line 464, in open
    response = self._open(req, data)
  File "C:\Python34\lib\urllib\request.py", line 482, in _open
    '_open', req)
  File "C:\Python34\lib\urllib\request.py", line 442, in _call_chain
    result = func(*args)
  File "C:\Python34\lib\urllib\request.py", line 1211, in http_open
    return self.do_open(http.client.HTTPConnection, req)
  File "C:\Python34\lib\urllib\request.py", line 1185, in do_open
    raise URLError(err)
urllib.error.URLError: <urlopen error [WinError 10060] A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond>

我已经明白，像这样的错误表示 Windows 设置有问题，建议 here（我正在运行 Windows 7），但我不明白它在 2.7 中的工作原理，而不是在 3.4 .

【问题讨论】：

以为他们改了包名...
建议：使用requests即可。
在 GNU/Linux 上使用 Python 3.2.3 可以正常工作。也许是 Windows 编译问题...
我在本地测试了这个（在 Windows 7；Python 3.5.0 上），它对我有用。
所以这不是python代码的问题，而是其他地方。我很想在这个项目中简单地使用 2.7，而不是试图追查问题，但我宁愿解决问题而不是避免它......

标签： python windows urlopen

【解决方案1】：

解决方案后，Python 2.7 代码开始抛出相同的错误。出于沮丧，我开始应用 microscoft 修复程序。我首先注销并重新登录。现在一切正常...

【讨论】：