python json匹配多个并替换

Question

在寻找解决方案时需要您的帮助。我有以下 json

[{"source":"AA","target":"BB","metric":"10","local_interface":"100","re​​mote_interface":"200"}, {"source":"AA","target":"BB","metric":"10","local_interface":"111","re​​mote_interface":"222"}, {"source":"BB","target":"AA","metric":"10","local_interface":"200","re​​mote_interface":"100"}]

目标是：

• 获取第一个元素（即：模式）作为源/目标/本地接口
• 在剩余元素中搜索与 source=pattern.target 、 target=pattern.source 、remote_interface=pattern.local_interface 匹配的元素
• 从 json 中移除元素。

希望这是有道理的。

Answer 1

你追求这么简单的事情吗？

j = [{"source":"AA","target":"BB","metric":"10",
 "local_interface":"100","remote_interface":"200"},
 {"source":"AA","target":"BB","metric":"10",
 "local_interface":"111","remote_interface":"222"},
 {"source":"BB","target":"AA","metric":"10",
 "local_interface":"200","remote_interface":"100"}]

s = j[0]["source"]
print(s)
t = j[0]["target"]
print(t)
li = j[0]["local_interface"]
print(li)

print('Find source ==', t)
for i in range(1,3):
  if j[i]['source'] == t:
    print("Is match:", j[i])

print()

del(j[1])
print("after deletion:", j)