【发布时间】:2017-11-01 09:35:01
【问题描述】:
我在 python 中结合 selenium 编写了一个脚本,以从启用了 javascript 的网页中获取一些数据。在点击下一页按钮之前需要做三件事,因为下一页链接仅在网页包含搜索结果时才会出现。这三件事是:填写两个搜索框并单击搜索按钮。但是,我的脚本可以完美地完成这三件事,但是当它应该单击下一页链接时会中断(抛出超时异常)。如您所见,我已经尝试了三种不同的选项来单击下一页链接,但从未成功。我尝试使用的其余两个已被注释掉。怎样才能成功点击下一页按钮?
我尝试过的脚本:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
driver = webdriver.Chrome()
wait = WebDriverWait(driver, 10)
driver.get("https://brokercheck.finra.org/")
wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, "[placeholder='Name or CRD#']"))).send_keys("Michael John")
wait.until(EC.presence_of_element_located((By.CSS_SELECTOR, "[placeholder='Firm Name or CRD# (optional)']"))).send_keys("Morgan Stanley")
wait.until(EC.presence_of_element_located((By.CSS_SELECTOR,'.md-button'))).click()
# wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR,'.pagination-next a'))).click()
# wait.until(EC.presence_of_element_located((By.CSS_SELECTOR,'.pagination-next a'))).click()
wait.until(EC.visibility_of_element_located((By.CSS_SELECTOR,'.pagination-next a'))).click()
driver.quit()
下一页链接所在的元素:
<ul class="pagination ng-pristine ng-untouched ng-valid ng-scope ng-isolate-scope" data-ng-if="listCtrl.getTotalResults()" total-items="listCtrl.getDisplayResults()" ng-model="listCtrl.currentPage" max-size="1" page-label="listCtrl.pageLabel($page)" items-per-page="listCtrl.itemsPerPage" ng-change="listCtrl.pageChanged()" boundary-links="true" previous-text="‹" next-text="›" first-text="«" last-text="»" aria-invalid="false">
<!-- ngIf: ::boundaryLinks --><li ng-if="::boundaryLinks" ng-class="{disabled: noPrevious()||ngDisabled}" class="pagination-first ng-scope disabled"><a href="" ng-click="selectPage(1, $event)" class="ng-binding">«</a></li><!-- end ngIf: ::boundaryLinks -->
<!-- ngIf: ::directionLinks --><li ng-if="::directionLinks" ng-class="{disabled: noPrevious()||ngDisabled}" class="pagination-prev ng-scope disabled"><a href="" ng-click="selectPage(page - 1, $event)" class="ng-binding">‹</a></li><!-- end ngIf: ::directionLinks -->
<!-- ngRepeat: page in pages track by $index --><li ng-repeat="page in pages track by $index" ng-class="{active: page.active,disabled: ngDisabled&&!page.active}" class="pagination-page ng-scope active"><a href="" ng-click="selectPage(page.number, $event)" class="ng-binding">1 of 27 pages</a></li><!-- end ngRepeat: page in pages track by $index -->
<!-- ngIf: ::directionLinks --><li ng-if="::directionLinks" ng-class="{disabled: noNext()||ngDisabled}" class="pagination-next ng-scope"><a href="" ng-click="selectPage(page + 1, $event)" class="ng-binding">›</a></li><!-- end ngIf: ::directionLinks -->
<!-- ngIf: ::boundaryLinks --><li ng-if="::boundaryLinks" ng-class="{disabled: noNext()||ngDisabled}" class="pagination-last ng-scope"><a href="" ng-click="selectPage(totalPages, $event)" class="ng-binding">»</a></li><!-- end ngIf: ::boundaryLinks -->
</ul>
【问题讨论】:
-
能不能给个网址
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当然,它在脚本中。
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好吧,有两件事,在传入keys之后url会改变,所以你需要先获取当前url,然后用标签传递这个类,然后点击
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也这样做了,但抛出了同样的异常。你不是说
driver.get(driver.current_url)然后我的其余代码要点击吗?
标签: python python-3.x selenium selenium-webdriver web-scraping