使用 Flask 显示 stackOverflow API JSON 数据

Question

我一直在尝试从 StackOverflow API 检索的 JSON 数据中显示我的用户名和声誉。

我正在使用 python 模块 Requests 来检索数据。 这是代码

from flask import Flask,jsonify
import requests
import simplejson 
import json

app = Flask(__name__)

@app.route("/")
def home():
    uri = "https://api.stackexchange.com/2.0/users?   order=desc&sort=reputation&inname=fuchida&site=stackoverflow"
    try:
        uResponse = requests.get(uri)
    except requests.ConnectionError:
       return "Connection Error"  
    Jresponse = uResponse.text
    return Jresponse

if __name__ == "__main__":
    app.run(debug = True)

未使用的导入是我完成这项工作所需要的，但似乎不知道如何完成它。 下面是返回给浏览器的内容，我只想显示用户名 [display_name] 和信誉。我有哪些选择才能完成这项工作？

{"items":[{"user_id":540028,"user_type":"registered","creation_date":1292207782,"display_name":"Fuchida","profile_image":"http://www.gravatar .com/avatar/6842025a595825e2de75dfc3058f0bee?d=identicon&r=PG","re​​putation":13,"reputation_change_day":0,"reputation_change_week":0,"reputation_change_month":0,"reputation_change_quarter":0,"reputation_change_year":0, "年龄":24,"last_access_date":1332905685,"last_modified_date":1332302766,"is_employee":false,"link":"http://stackoverflow.com/users/540028/fuchida","website_url":"http ://blog.Fuchida.me","位置":"明尼阿波利斯 MN","account_id":258084,"badge_counts":{"gold":0,"silver":0,"bronze":3}}],"quota_remaining":282,"quota_max":300,"has_more" :假}

Answer 1

使用 json.loads() 读取和解码数据。

from flask import Flask,jsonify
import requests
import simplejson 
import json

app = Flask(__name__)

@app.route("/")
def home():
    uri = "https://api.stackexchange.com/2.0/users?   order=desc&sort=reputation&inname=fuchida&site=stackoverflow"
    try:
        uResponse = requests.get(uri)
    except requests.ConnectionError:
       return "Connection Error"  
    Jresponse = uResponse.text
    data = json.loads(Jresponse)

    displayName = data['items'][0]['display_name']# <-- The display name
    reputation = data['items'][0]['reputation']# <-- The reputation

    return Jresponse

if __name__ == "__main__":
    app.run(debug = True)