MDX 尺寸计算答案

【问题标题】：MDX COUNT ON DIMENSIONMDX 尺寸计算
【发布时间】：2015-03-23 07:37:21
【问题描述】：

我有一个 mdx 查询，它可以为我提供不同的 eid、地区和国家/地区：

SELECT ([Measures].[Active Tiles Count]) ON 0,
NON EMPTY ([Employee].[Employee Id].Children,[Employee - Business Region].  [Region Code].Children,[Employee - Country].[Country Code].Children) ON 1
FROM [OLAP Pre]
WHERE ( 
{[Employee Statuses].[Status Id].&[1],[Employee Statuses].[Status Id].&[4],[Employee Statuses].[Status Id].&[3]},
{[Business Region].[Abbreviation].&[APJ],[Business Region].[Abbreviation].&[EMEA],[Business Region].[Abbreviation].&[Americas]},
{[Employee Types].[Bits].&[1],[Employee Types].[Bits].&[9],
[Employee Types].[Bits].&[25],[Employee Types].[Bits].&[5],
[Employee Types].[Bits].&[13],[Employee Types].[Bits].&[29]}
,{[Date].[Date].&[2015-03-18T00:00:00]:NULL})

但我希望按地区和国家/地区分组 COUNT(DISTINCT(employEEid))。
如何做到这一点？

【问题讨论】：

标签： count mdx dimensions

【解决方案1】：

创建一个 DISTINCT COUNT MEASURE，它是一个预定义的聚合类型

【讨论】：

【解决方案2】：

尝试使用DISTINCTCOUNT函数

WITH MEMBER Measures.[CountOfDistinctEmployes] AS
DISTINCTCOUNT([Employee].[Employee Id].Children)

SELECT {[Measures].[Active Tiles Count], Measures.[CountOfDistinctEmployes]} ON 0,
NON EMPTY ([Employee].[Employee Id].Children,[Employee - Business Region].  [Region Code].Children,[Employee - Country].[Country Code].Children) ON 1
FROM [OLAP Pre]
WHERE ( 
{[Employee Statuses].[Status Id].&[1],[Employee Statuses].[Status Id].&[4],[Employee Statuses].[Status Id].&[3]},
{[Business Region].[Abbreviation].&[APJ],[Business Region].[Abbreviation].&[EMEA],[Business Region].[Abbreviation].&[Americas]},
{[Employee Types].[Bits].&[1],[Employee Types].[Bits].&[9],
[Employee Types].[Bits].&[25],[Employee Types].[Bits].&[5],
[Employee Types].[Bits].&[13],[Employee Types].[Bits].&[29]}
,{[Date].[Date].&[2015-03-18T00:00:00]:NULL})

【讨论】：