在Python中将两个空列表之间的所有列表（字符串列表）合并为一个列表

Question

我想将两个空列表之间的所有列表转换为一个列表。示例

    []
    ['The', 'tablets', 'are', 'filled', 'into', 'cylindrically', 'shaped', 'bottles', 'made', 'of', 'white', 'coloured']
    ['polyethylene.', 'The', 'volumes', 'of', 'the', 'bottles', 'depend', 'on', 'the', 'tablet', 'strength', 'and', 'amount', 'of']
    ['tablets,', 'ranging', 'from', '20', 'to', '175', 'ml.', 'The', 'screw', 'type', 'cap', 'is', 'made', 'of', 'white', 'coloured']
    ['polypropylene', 'and', 'is', 'equipped', 'with', 'a', 'tamper', 'proof', 'ring.']
    []
    ['PVC/PVDC', 'blister', 'pack']
    []
    ['Blisters', 'are', 'made', 'in', 'a', 'thermo-forming', 'process', 'from', 'a', 'PVC/PVDC', 'base', 'web.', 'Each', 'tablet']
    ['is', 'filled', 'into', 'a', 'separate', 'blister', 'and', 'a', 'lidding', 'foil', 'of', 'aluminium', 'is', 'welded', 'on.', 'The', 'blisters']
    ['are', 'opened', 'by', 'pressing', 'the', 'tablets', 'through', 'the', 'lidding', 'foil.', 'PVDC', 'foil', 'is', 'in', 'contact', 'with']
    ['the', 'tablets.']
    []
    ['Aluminium', 'blister', 'pack']
    []

我想要的第一个列表是：

['The', 'tablets', 'are', 'filled', 'into', 'cylindrically', 'shaped', 'bottles', 'made', 'of', 'white', 'coloured', 'polyethylene.', 'The', 'volumes', 'of', 'the', 'bottles', 'depend', 'on', 'the', 'tablet', 'strength', 'and', 'amount', 'of', 'tablets,', 'ranging', 'from', '20', 'to', '175', 'ml.', 'The', 'screw', 'type', 'cap', 'is', 'made', 'of', 'white', 'coloured','polypropylene', 'and', 'is', 'equipped', 'with', 'a', 'tamper', 'proof', 'ring.'] 

下一个列表变成：

['PVC/PVDC', 'blister', 'pack']

并且模式应该继续。 到目前为止的代码：

import csv, re
filepath = r'C:\Users\techj\Music\Data\Tagged\090388 (1.0,CURRENT,LATEST APPROVED.txt)'

with open(filepath) as f:
        content = f.readlines()
#        s = ' '.join(x for x in content if x)
#        print(s)

        for line in content:
            line = line.split()
            print(line)

Answer 1

这可能不是您要查找的内容，但我认为您正在尝试从文件中读取段落。这段代码会给你段落：

with open(path) as f:
    data=f.read()
paragraphs=data.split("\n\n")

现在，如果您想要每个段落中的单词，您可以用空格分隔它们：

all_words=[]
for paragraph in paragraphs:
    words=paragraph.split(" ")
    all_words.append(words)
print(all_words)

Answer 2

由于我无权访问您的文件，但我想测试我的算法，因此我创建了两个生成器函数，它们会将输入行生成为字符串列表。第一个生成器函数基于您的代码读取文件并将每一行拆分为字符串列表。第二个，我用于测试，使用字符串列表的预拆分列表。您只需将调用 line_producer_2 替换为调用 line_producer_1 即可从文件中获取输入。

def line_producer_1():
    import csv, re
    filepath = r'C:\Users\techj\Music\Data\Tagged\090388 (1.0,CURRENT,LATEST APPROVED.txt)'

    with open(filepath) as f:
            content = f.readlines()
    #        s = ' '.join(x for x in content if x)
    #        print(s)

            for line in content:
                line = line.split()
                yield line

def line_producer_2():
    lines = [
        [],
        ['The', 'tablets', 'are', 'filled', 'into', 'cylindrically', 'shaped', 'bottles', 'made', 'of', 'white', 'coloured'],
        ['polyethylene.', 'The', 'volumes', 'of', 'the', 'bottles', 'depend', 'on', 'the', 'tablet', 'strength', 'and', 'amount', 'of'],
        ['tablets,', 'ranging', 'from', '20', 'to', '175', 'ml.', 'The', 'screw', 'type', 'cap', 'is', 'made', 'of', 'white', 'coloured'],
        ['polypropylene', 'and', 'is', 'equipped', 'with', 'a', 'tamper', 'proof', 'ring.'],
        [],
        ['PVC/PVDC', 'blister', 'pack'],
        [],
        ['Blisters', 'are', 'made', 'in', 'a', 'thermo-forming', 'process', 'from', 'a', 'PVC/PVDC', 'base', 'web.', 'Each', 'tablet'],
        ['is', 'filled', 'into', 'a', 'separate', 'blister', 'and', 'a', 'lidding', 'foil', 'of', 'aluminium', 'is', 'welded', 'on.', 'The', 'blisters'],
        ['are', 'opened', 'by', 'pressing', 'the', 'tablets', 'through', 'the', 'lidding', 'foil.', 'PVDC', 'foil', 'is', 'in', 'contact', 'with'],
        ['the', 'tablets.'],
        [],
        ['Aluminium', 'blister', 'pack'],
        [],
    ]
    for line in lines:
        yield line

accumulated_lines = []
for line in line_producer_2():
    if line:
        accumulated_lines.extend(line)
    elif accumulated_lines:
        print(accumulated_lines)
        accumulated_lines = []
if accumulated_lines:
    print(accumulated_lines)

打印：

['The', 'tablets', 'are', 'filled', 'into', 'cylindrically', 'shaped', 'bottles', 'made', 'of', 'white', 'coloured', 'polyethylene.', 'The', 'volumes', 'of', 'the', 'bottles', 'depend', 'on', 'the', 'tablet', 'strength', 'and', 'amount', 'of', 'tablets,', 'ranging', 'from', '20', 'to', '175', 'ml.', 'The', 'screw', 'type', 'cap', 'is', 'made', 'of', 'white', 'coloured', 'polypropylene', 'and', 'is', 'equipped', 'with', 'a', 'tamper', 'proof', 'ring.']
['PVC/PVDC', 'blister', 'pack']
['Blisters', 'are', 'made', 'in', 'a', 'thermo-forming', 'process', 'from', 'a', 'PVC/PVDC', 'base', 'web.', 'Each', 'tablet', 'is', 'filled', 'into', 'a', 'separate', 'blister', 'and', 'a', 'lidding', 'foil', 'of', 'aluminium', 'is', 'welded', 'on.', 'The', 'blisters', 'are', 'opened', 'by', 'pressing', 'the', 'tablets', 'through', 'the', 'lidding', 'foil.', 'PVDC', 'foil', 'is', 'in', 'contact', 'with', 'the', 'tablets.']
['Aluminium', 'blister', 'pack']

See Demo

Answer 3

试试这个，

filepath = r'C:\Users\techj\Music\Data\Tagged\090388 (1.0,CURRENT,LATEST APPROVED.txt)'

with open(filepath, 'r') as file:
    _temp = []
    for line in file:
        _line = line.split()
        if _line:
            _temp+=_line
        else:
            print(_temp)
            _temp = []

对于 python 3.8，

with open(filepath, 'r') as file:
    _temp = []
    for line in file: 
        if (_line:=line.split()):
            _temp+=_line
        else:
            print(_temp)
            _temp = []