Spring MVC 无法处理来自 Resource Handler 的 404？

Question

我正在使用 Spring MVC 4.3.11.RELEASE 并有一个用于静态资源的 vanilla 资源处理程序。它工作正常 - 对于存在的资源。但是，如果不是，它似乎会向 DispatcherServlet 返回一个 404，因为它找到了一个处理程序，所以它对该响应感到满意。我有用于 NoHandlerFoundException 的 ControllerAdvice，它适用于控制器，但并不意味着处理这种情况。所以 Spring MVC 完全退出，我得到了讨厌的 Tomcat 404 响应。我无法为这种情况配置处理，因此我可以返回正确的响应。

为 Spring 启用 TRACE 后，您会看到以下请求：

2018-03-15T14:22:05,361 TRACE [] DispatcherServlet          - Bound request context to thread: org.apache.catalina.connector.RequestFacade@597aa896
2018-03-15T14:22:05,361 DEBUG [] DispatcherServlet          - DispatcherServlet with name 'dispatcher' processing GET request for [/creditcard/static/doh]
2018-03-15T14:22:05,361 TRACE [] DispatcherServlet          - Testing handler map [org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerMapping@4b720a14] in DispatcherServlet with name 'dispatcher'
2018-03-15T14:22:05,361 DEBUG [] questMappingHandlerMapping - Looking up handler method for path /static/doh
2018-03-15T14:22:05,364 DEBUG [] questMappingHandlerMapping - Did not find handler method for [/static/doh]
2018-03-15T14:22:05,364 TRACE [] DispatcherServlet          - Testing handler map [org.springframework.web.servlet.handler.BeanNameUrlHandlerMapping@67db7dde] in DispatcherServlet with name 'dispatcher'
2018-03-15T14:22:05,364 TRACE [] BeanNameUrlHandlerMapping  - No handler mapping found for [/static/doh]
2018-03-15T14:22:05,364 TRACE [] DispatcherServlet          - Testing handler map [org.springframework.web.servlet.handler.SimpleUrlHandlerMapping@4698270f] in DispatcherServlet with name 'dispatcher'
2018-03-15T14:22:05,364 DEBUG [] SimpleUrlHandlerMapping    - Matching patterns for request [/static/doh] are [/static//**]
2018-03-15T14:22:05,364 DEBUG [] SimpleUrlHandlerMapping    - URI Template variables for request [/static/doh] are {}
2018-03-15T14:22:05,364 DEBUG [] SimpleUrlHandlerMapping    - Mapping [/static/doh] to HandlerExecutionChain with handler [ResourceHttpRequestHandler [locations=[ServletContext resource [/static//]], resolvers=[org.springframework.web.servlet.resource.PathResourceResolver@20537c7e]]] and 1 interceptor
2018-03-15T14:22:05,364 TRACE [] DispatcherServlet          - Testing handler adapter [org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerAdapter@442b38d3]
2018-03-15T14:22:05,364 TRACE [] DispatcherServlet          - Testing handler adapter [org.springframework.web.servlet.mvc.HttpRequestHandlerAdapter@3128c8a7]
2018-03-15T14:22:05,364 DEBUG [] DispatcherServlet          - Last-Modified value for [/creditcard/static/doh] is: -1
2018-03-15T14:22:05,364 TRACE [] ResourceHttpRequestHandler - Applying "invalid path" checks to path: doh
2018-03-15T14:22:05,364 TRACE [] PathResourceResolver       - Resolving resource for request path "doh"
2018-03-15T14:22:05,364 TRACE [] PathResourceResolver       - Checking location: ServletContext resource [/static//]
2018-03-15T14:22:05,364 TRACE [] PathResourceResolver       - No match for location: ServletContext resource [/static//]
2018-03-15T14:22:05,364 TRACE [] ResourceHttpRequestHandler - No matching resource found - returning 404
2018-03-15T14:22:05,364 DEBUG [] DispatcherServlet          - Null ModelAndView returned to DispatcherServlet with name 'dispatcher': assuming HandlerAdapter completed request handling
2018-03-15T14:22:05,364 TRACE [] DispatcherServlet          - Cleared thread-bound request context: org.apache.catalina.connector.RequestFacade@597aa896
2018-03-15T14:22:05,364 DEBUG [] DispatcherServlet          - Successfully completed request

想法？

Answer 1

我有同样的问题。我的解决方案如下：

• spring.resources.add-mappings=false（在 yaml 或 application.properties 中）

• 在 WebMvcConfigurer 'addResourceHandlers' 方法的 Config 中添加所有映射，例如：

  @Configuration
  public class WebMvcConfig implements WebMvcConfigurer {
      @Override
      public void addResourceHandlers(ResourceHandlerRegistry registry) {
          registry.addResourceHandler("/home.html**")
                  .addResourceLocations("classpath:/static/views/home/");
      }
  
      @Override
      public void configureDefaultServletHandling(
                DefaultServletHandlerConfigurer configurer) {
          // DO not enable this ! 
          // configurer.enable();
          // Remove this method! 
      }
  }
  

• 必须删除默认的 servlet 处理程序，因为它会尝试处理并返回状态 404，但不会抛出 NoHandlerFoundException

• 添加 GlobalExceptionHandler 控制器建议：

  @ControllerAdvice
  public class GlobalExceptionHandler {
      @ExceptionHandler(NoHandlerFoundException.class)
      public String handleNotFoundError(Exception ex) {
          return "redirect:/your404page";
      }
  }
  

希望这会有所帮助！对我来说，它完美无缺！

Answer 2

mrkurtan 答案仅适用于 spring-boot，因为 spring.resources.add-mappings=false 是 spring-boot 配置

所以重写所需的配置以通过 NoHandlerFoundException 并处理它。

1. 创建一个带有@ControllerAdvice注解的类GlobalExceptionHandler

@ControllerAdvice
public class GlobalExceptionHandler 
{
    @ExceptionHandler(NoHandlerFoundException.class)
    public String handleNotFoundError(Exception ex) 
    {
        return "redirect:/yourCustom404page";
    }
}

1. 默认情况下，当页面/资源不存在时，servlet 容器将抛出默认的 404 页面。如果您想要自定义 404 响应，则需要告诉 DispatcherServlet 在未找到处理程序时抛出异常。我们可以通过将throwExceptionIfNoHandlerFound servlet 初始化参数设置为true 来做到这一点

在spring-mvc中基于java的配置是

public class AppInitializer extends AbstractAnnotationConfigDispatcherServletInitializer
{
    ...

    @Override
    protected DispatcherServlet createDispatcherServlet(WebApplicationContext servletAppContext) 
    {
        final DispatcherServlet servlet = (DispatcherServlet) super.createDispatcherServlet(servletAppContext);
        servlet.setThrowExceptionIfNoHandlerFound(true);
        return servlet;
    }

}

如果是基于 xml 的配置，像这样初始化你的调度器 servlet

<servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>throwExceptionIfNoHandlerFound</param-name>
        <param-value>true</param-value>
    </init-param>
</servlet>