【发布时间】:2023-03-22 18:24:01
【问题描述】:
有没有办法获取入口小部件的状态当前状态?我以为我可以使用 .winfo 方法,但似乎并非如此?尝试创建一个功能/按钮,根据条目小部件的状态进行不同的操作...到目前为止,没有运气...有什么想法吗?
Entry 和 Button 小部件:
self.contact_phone = tk.Entry(contact_frame, font='arial 10 bold', relief='flat', bg='grey60', textvariable=self.var3, state='readonly', readonlybackground='grey60')
self.contact_phone.place(anchor='nw', y=50)
self.change_phone = tk.Button(contact_frame, text='Change', font='arial 10 bold', bd=2, bg='grey80', command=self.changephone)
self.change_phone.place(anchor='nw', y=48, x=180)
建议的功能(为简洁起见,省略了打开/写入文件内容):
def changephone(self):
if #the state of the widget is readonly:
'''config the widget to allow entry'''
self.contact_phone.config(state='normal', relief='sunken', bg='white', bd=2)
'''change the text on the button to reflect the other functionality'''
self.change_phone.config(text='Apply')
elif #the state of the widget is normal:
'''get the new contents and write it to a file'''
newnumber = self.contact_phone.get()
#open a file and write the new number to it...
'''return the widget and button to their previous states'''
self.contact_phone.config(state='readonly', relief='sunken', readonlybackground='grey60')
self.change_phone.config(text='Change')
谢谢,
迈克
【问题讨论】:
-
阅读
cget方法。 -
太棒了!谢谢!完全忘记了它的存在……
标签: python function tkinter widget state