django模板中的字典

Question

我有这样的看法：

info_dict =  [{u'Question 1': ['13365', '13344']}, {u'Question 2': ['13365']}, {u'Question 3': []}]

for key in info_dict:
    for k, v in key.items():
        profile = User.objects.filter(id__in=v, is_active=True)
    for f in profile:
        wanted_fields = ['job', 'education', 'country', 'city','district','area']
        profile_dict = {}
        for w in wanted_fields:
            profile_dict[f._meta.get_field(w).verbose_name] = getattr(f, w).name

return render_to_response('survey.html',{
    'profile_dict':profile_dict,
},context_instance=RequestContext(request))

在模板中：

<ul>
    {% for k, v in profile_dict.items %}
        <li>{{ k }} : {{ v }}</li>
    {% endfor %}
</ul>

我在模板中只有一本字典。但是 4 字典可能在这里（因为 info_dict） 观点有什么问题？

提前致谢

Answer 1

在您看来，您只创建了一个变量 (profile_dict) 来保存配置文件字典。

在for f in profile 循环的每次迭代中，您都在重新创建该变量，并用新字典覆盖它的值。因此，当您在传递给模板的上下文中包含 profile_dict 时，它会保存分配给 profile_dict 的最后一个值。

如果你想将四个 profile_dicts 传递给模板，你可以在你的视图中这样做：

info_dict =  [{u'Question 1': ['13365', '13344']}, {u'Question 2': ['13365']}, {u'Question 3': []}]

# Create a list to hold the profile dicts
profile_dicts = []

for key in info_dict:
    for k, v in key.items():
        profile = User.objects.filter(id__in=v, is_active=True)
    for f in profile:
        wanted_fields = ['job', 'education', 'country', 'city','district','area']
        profile_dict = {}
        for w in wanted_fields:
            profile_dict[f._meta.get_field(w).verbose_name] = getattr(f, w).name

        # Add each profile dict to the list
        profile_dicts.append(profile_dict)

# Pass the list of profile dicts to the template
return render_to_response('survey.html',{
    'profile_dicts':profile_dicts,
},context_instance=RequestContext(request))

然后在你的模板中：

{% for profile_dict in profile_dicts %}
<ul>
    {% for k, v in profile_dict.items %}
        <li>{{ k }} : {{ v }}</li>
    {% endfor %}
</ul>
{% endfor %}