假设您在某个 NumPy 数组中存储了 2D(僵尸攻击)数据,我将使用 Matplotlib's colormaps 从标准化数据生成热图,参见。 this Q&A。然后,我将该热图与(浣熊市)图像混合。因此,在颜色图中也有一些 alpha 透明度会很好,参见。 this Q&A.
这里有一些代码:
import cv2
from matplotlib.colors import ListedColormap # Needed for custom colormap
from matplotlib.pyplot import cm, Normalize # Needed for heatmap
import numpy as np
from scipy.stats import multivariate_normal # Needed for mockup data
# Read image
image = cv2.imread('R42nH.jpg')
# Generate mockup data
h, w = image.shape[:2]
x = np.arange(w)
y = np.arange(h)
X, Y = np.meshgrid(x, y)
pos = np.dstack((X, Y))
mus = [[200, 100], [300, 400], [500, 150]]
covs = [[[300, 155], [175, 550]], [[400, -100], [40, 250]], [[150, 10], [35, 200]]]
zombies = np.zeros((h, w), np.float64)
for mu, cov in zip(mus, covs):
rv = multivariate_normal(mu, cov)
Z = rv.pdf(pos)
zombies += Z / np.max(Z)
zombies /= np.max(zombies)
# Generate custom colormap with alpha channel,
# cf. https://stackoverflow.com/a/37334212/11089932
cmap = cm.autumn_r
c_cmap = cmap(np.arange(cmap.N))
c_cmap[:, -1] = np.linspace(0, 1, cmap.N)
c_cmap = ListedColormap(c_cmap)
# Generate heatmap, cf. https://stackoverflow.com/a/31546410/11089932
norm = Normalize(vmin=zombies.min(), vmax=zombies.max())
heatmap = c_cmap(norm(zombies))
# Blend image with heatmap
heatmap = cv2.cvtColor(np.uint8(heatmap * 255), cv2.COLOR_RGBA2BGRA)
alpha = heatmap[..., 3] / 255
alpha = np.tile(np.expand_dims(alpha, axis=2), [1, 1, 3])
output = (image * (1 - alpha) + heatmap[..., :3] * alpha).astype(np.uint8)
# Output
cv2.imshow('Zombie Attack', output)
cv2.waitKey(0)
cv2.destroyAllWindows()
热图如下所示:
最后的输出是这样的:
请检查您是否可以将数据输入该管道,以及结果是否符合您的想法。
整个颜色图上的线性 alpha 透明度可能不是那么有益,如果您还希望即使对于较低(僵尸攻击)数字也具有“显着”颜色。也许然后手动调整 alpha 透明度。
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System information
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Platform: Windows-10-10.0.16299-SP0
Python: 3.9.1
PyCharm: 2021.1
Matplotlib: 3.4.1
NumPy: 1.20.2
OpenCV: 4.5.1
SciPy: 1.6.2
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