【问题标题】:Matplotlib lib 3d surface plot with 4th dimension as colorMatplotlib lib 3d 曲面图,以第 4 维为颜色
【发布时间】:2018-10-09 07:13:06
【问题描述】:

在遵循here 提供的解决方案之后,我发现情节看起来不像我期望的那样。

z轴最大值不超过5.89。然而,据我所知,我们看到 Z 轴取 Z1 的值。

我想知道问题可能出在哪里。

import matplotlib
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
import numpy as np

x = [10.0, 14.0, 18.0, 14.0, 6.0, 6.0, 2.0, 18.0, 18.0, 6.0, 18.0, 14.0, 10.0, 10.0, 6.0, 6.0, 10.0, 14.0, 2.0, 18.0, 10.0, 14.0]
y = [1.8, 1.4, 1.2, 2.0, 2.0, 1.4, 2.0, 1.8, 2.0, 1.8, 1.6, 1.8, 2.0, 1.2, 1.6, 1.2, 1.6, 1.2, 1.8, 1.4, 1.4, 1.6]
z = [1.22, 2.14, 1.66, 0.7, 2.86, 5.89, 3.85, 0.45, 0.4, 4.28, 0.6, 0.92, 0.67, 3.52, 5.25, 4.94, 1.37, 3.76, 4.75, 0.95, 1.99, 1.41]
z1 = [29.0, 26.72, 26.71, 31.33, 29.46, 24.84, 32.54, 31.43, 33.84, 28.14, 29.84, 31.34, 30.51, 25.0, 25.73, 24.06, 27.09, 26.89, 29.85, 28.93, 26.58, 27.53]


# domains
x = np.array(x)
y = np.array(y)
z = np.array(z)
z1 = np.array(z1)

# convert to 2d matrices
Z = np.outer(z.T, z)        # 50x50
Z1 = np.outer(z1.T, z1)        # 50x50
X, Y = np.meshgrid(x, y)    # 50x50

# fourth dimention - colormap
# create colormap according to x-value (can use any 50x50 array)
color_dimension = Z1 # change to desired fourth dimension
minn, maxx = color_dimension.min(), color_dimension.max()
norm = matplotlib.colors.Normalize(minn, maxx)
m = plt.cm.ScalarMappable(norm=norm, cmap='jet')
m.set_array([])
fcolors = m.to_rgba(color_dimension)

# plot
fig = plt.figure()
ax = fig.gca(projection='3d')
ax.plot_surface(X,Y,Z, rstride=1, cstride=1, facecolors=fcolors, vmin=minn, vmax=maxx, shade=False)
ax.set_xlabel('x')
ax.set_ylabel('y')
ax.set_zlabel('z')
fig.canvas.draw()
fig.savefig('test.pdf')

【问题讨论】:

    标签: python matplotlib


    【解决方案1】:

    你拿外积:

    Z = np.outer(z.T, z)        # 50x50
    

    因此,您的 Z 矩阵中的最大值是 5.89*5.89=34.69,您的绘图似乎是正确的。

    您可能想要的是使用来自 scipy 或 matplotlib 方法的griddata 在网格上插入不规则间隔的数据,请参阅Contour plot of irregularly spaced data

    正如this post 中所建议的,您也可以使用griddata 作为颜色。完整的示例(此处使用 matplotlib.tri 的插值)如下所示:

    import numpy as np
    import matplotlib.pyplot as plt
    from matplotlib import cm
    from mpl_toolkits.mplot3d import Axes3D
    import matplotlib.tri as tri
    from matplotlib.colors import Normalize
    
    x = [10.0, 14.0, 18.0, 14.0, 6.0, 6.0, 2.0, 18.0, 18.0, 6.0, 18.0, 14.0, 10.0, 10.0, 6.0, 6.0, 10.0, 14.0, 2.0, 18.0, 10.0, 14.0]
    y = [1.8, 1.4, 1.2, 2.0, 2.0, 1.4, 2.0, 1.8, 2.0, 1.8, 1.6, 1.8, 2.0, 1.2, 1.6, 1.2, 1.6, 1.2, 1.8, 1.4, 1.4, 1.6]
    z = [1.22, 2.14, 1.66, 0.7, 2.86, 5.89, 3.85, 0.45, 0.4, 4.28, 0.6, 0.92, 0.67, 3.52, 5.25, 4.94, 1.37, 3.76, 4.75, 0.95, 1.99, 1.41]
    z1 = [29.0, 26.72, 26.71, 31.33, 29.46, 24.84, 32.54, 31.43, 33.84, 28.14, 29.84, 31.34, 30.51, 25.0, 25.73, 24.06, 27.09, 26.89, 29.85, 28.93, 26.58, 27.53]
    
    
    # domains
    x = np.array(x)
    y = np.array(y)
    z = np.array(z)
    z1 = np.array(z1)
    
    # Create grid values first.
    ngridx = 100
    ngridy = 100
    xi = np.linspace(x.min(), x.max(), ngridx)
    yi = np.linspace(y.min(), y.max(), ngridy)
    
    # Perform linear interpolation of the data (x,y)
    # on a grid defined by (xi,yi)
    triang = tri.Triangulation(x, y)
    interpolator_z = tri.LinearTriInterpolator(triang, z)
    interpolator_z1 = tri.LinearTriInterpolator(triang, z1)
    Xi, Yi = np.meshgrid(xi, yi)
    zi = interpolator_z(Xi, Yi)
    z1i = interpolator_z1(Xi, Yi)
    
    X, Y, Z, Z1 = xi, yi, zi, z1i
    
    fig = plt.gcf()
    ax1 = fig.add_subplot(111, projection='3d')
    
    minn, maxx = z1.min(), z1.max()
    norm = Normalize()
    surf = ax1.plot_surface(X,Y,Z, rstride=1, cstride=1, facecolors=cm.jet(norm(Z1)), vmin=minn, vmax=maxx, shade=False)
    
    m = cm.ScalarMappable(cmap=cm.jet)
    m.set_array(Z1)
    col = plt.colorbar(m)
    plt.show()
    

    感谢 ImportanceOfBeingErnest 指出 matplotlib 中的 griddata 已被弃用并提供指向当前示例的链接。

    【讨论】:

    • 我们如何实际构建它以使 Z 轴采用 z 而不是 max(z)*max(z) 的值?
    • 您是否建议使用 griddata 而不是 plot_surface?
    • 不,代替meshgrid和外积。但这只是我根据您提供的信息所做的假设。
    • z1 必须定义我的做法?
    • z1是什么意思?你想让剧情表现什么?对我来说,您似乎有一些数据点,例如在散点图中,并且想要将这些插入到表面上。这就是您对 griddata 所做的事情。但是我不太了解z1组件
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