AngularJS从JSON的缩略图中获取模态图像

Question

使用AngularJS获取JSON文件：

{
 "albumId": 1,
 "id": 1,
 "title": "accusamus beatae ad facilis cum similique qui sunt",
 "url": "http://placehold.it/600/92c952",
 "thumbnailUrl": "http://placehold.it/150/92c952"
},

并使用 ng-repeat 显示：

<div ng-repeat="image in images" class="col-xs-2 ">
   <div class="thumbnail">
      <img src="{{ image.thumbnailUrl }}" alt="" ng-click="open()" />

   </div>
</div>

这行得通。比我将 ui.bootstrap 连接到缩略图以打开模式窗口。

控制器：

    app.controller("page3Ctrl",['$scope', '$resource', '$uibModal', function ($scope, $resource,$uibModal) {

    var postingsResource = $resource('http://jsonplaceholder.typicode.com/photos', {});
    $scope.images = postingsResource.query();


    $scope.open = function() {
        var uibModalInstance = $uibModal.open({
            animation: true,
            templateUrl: 'modal.html'

        });
    };

}]);

工作正常。现在，我怎么可能从 thumbnailUrl 在模态 url 中显示特定图像？它们应该匹配。

Answer 1

如果您没有为modal 使用任何控制器，那么您可以简单地将$scope 分配为模态范围，并将所选图像分配给scope 变量并在模态模板中访问它。

var app = angular.module('app', ['ngResource','ui.bootstrap']);
app.run(function($templateCache){
  $templateCache.put('modal.html', '<div><a ng-click="$close(true)" class="pull-right">&times close</a><img ng-src="{{currentImage.url}}"/></div>');
});
app.controller("page3Ctrl", ['$scope', '$resource', '$uibModal', function($scope, $resource, $uibModal) {

  var postingsResource = $resource('http://jsonplaceholder.typicode.com/photos', {});
  $scope.images = postingsResource.query();

 //no controller for modal
  $scope.open = function(image) {
    $scope.currentImage = image;
    var uibModalInstance = $uibModal.open({
      animation: true,
      scope:$scope,
      templateUrl: 'modal.html'
    });
  };
  
  /*
  //modal has controller
  $scope.open = function(image) {
    var uibModalInstance = $uibModal.open({
      animation: true,
      templateUrl: 'modal.html',
      resolve: {
        image: function(){
          return image;
        }
      },
      controller: function($scope, image){
        $scope.currentImage = image;
      }
    });
  };
  */

}]);

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.5.11/angular.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/angular-resource/1.5.11/angular-resource.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/angular-ui-bootstrap/2.5.0/ui-bootstrap.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/angular-ui-bootstrap/2.5.0/ui-bootstrap-tpls.min.js"></script>
<link href="//netdna.bootstrapcdn.com/twitter-bootstrap/2.3.1/css/bootstrap-combined.min.css" rel="stylesheet">
<div ng-app="app" ng-controller="page3Ctrl">
  <div ng-repeat="image in images.slice(0,10)" class="col-xs-2 ">
    <div class="thumbnail" ng-click="open(image)">
      <img ng-src="{{ image.thumbnailUrl }}" alt="" ng-click="open()" />

    </div>
  </div>
</div>

Answer 2

您可以向open 函数添加一个参数，并将图像的url 传递给它。像这样：

$scope.open = function(imageUrl) {
    var uibModalInstance = $uibModal.open({
        animation: true,
        templateUrl: 'modal.html',
        controller: ModalInstanceCtrl,
        resolve: {
           imageUrl: function () {
             return imageUrl;
           }
        }
    });
}

所以：

<img src="{{ image.thumbnailUrl }}" alt="" ng-click="open(image.url)" />

参数也必须传递给模态控制器：

var ModalInstanceCtrl = function ($scope, $modalInstance, imageUrl) {
    $scope.imageUrl = imageUrl;
};

有关将值传递给模态控制器的更多详细信息：Pass parameter to modal