如果字符串在列表 [0] 中，python list.index('') 无法在列表中找到字符串 - 为什么？我怎么找到它？

Question

我要疯了吗？

在我的测试中，如果字符串在列表 [0] 中，python list.index('') 无法在列表中找到字符串！！！

为什么？我怎么找到它？

这是我的示例代码：

list1 = ['WTF', '2.09', '\xc2\x80document.write(CurrencyFormat(Currency.convert((209/100),"GBP","EUR")));','0.00', 'Feminised', '6.88', '\xc2\x80document.write(CurrencyFormat(Currency.convert((688/100),"GBP","EUR")));', 'Regular', 'x10', '20.90', '\xc2\x80document.write(CurrencyFormat(Currency.convert((2090/100),"GBP","EUR")));', 'Feminised', 'x12', '82.56', '\xc2\x80document.write(CurrencyFormat(Currency.convert((8256/100),"GBP","EUR")));']
list2 = ['1','2','3','4','5', '1']
if list1.index('0.00'):
    print "I found 0.00 in list 1 but if its in position[0], I cannot find it using index('0.00') - even it appears twice what gives?"
if list2.index('1'):
    print 'weird'
else:
    print 'I did not find 1 in list 2 even thought it is definitely there (twice infact)... WTF?'
print 'I can find it like this but I want to search by string >>> ' + list2[0]
print 'Or like this like this but I want to search by string >>> ' + list2[-1]

这给了我以下结果：

I found 0.00 in list 1 but if its in position[0], I cannot find it using index('0.00') - even it appears twice what gives?
I did not find 1 in list 2 even thought it is definitely there (twice infact)... WTF?
I can find it like this but I want to search by string >>> 1
Or like this like this but I want to search by string >>> 1

我想我一定遗漏了一些非常明显的东西...但无法弄清楚或找到答案...请通过搜索字符串帮助我在 list1 中找到“WTF”或在 list2 中找到“1”... ..

Answer 1

当您执行if list1.index('1') 时，您正在测试该列表中'1' 的索引是否为布尔真。它的索引为零，这是布尔假。所以你的 if 块没有运行。

如果你想知道它是否在里面，只需if '1' in list1。