在列表python中用逗号分割字符串[关闭]

Question

我有这份清单

l = [[hello,world],[i need help, python]] 
l [0] = [hello, world] 
l [1] = [i need help, python]

我需要用逗号分隔l[0] 和l[1]，但我不知道该怎么做 因为"hello, world" 和"i need help, python" 是字符串。

谁能帮帮我！

Answer 1

这是我用于解决此类问题的递归方法...

def explode(sep,x):
    if isinstance(x,(str,unicode)): return x.split(sep)
    elif isinstance(x,list): return [explode(sep,each) for each in x]
    elif isinstance(x,dict):return {key:explode(sep,x[key]) for key in x}
    else: raise ValueError("function doesn't support",type(x))

l = [["hello,world"],["i need help, python"]] 
l = explode(",",l)

Answer 2

只需遍历列表并使用 myString.split(",") 拆分每个条目

Answer 3

我想你想循环遍历列表：

>>> l = [['hello,world'],['i need help, python']] 
>>> for x in l:
...     print x[0]       # if you sung python 3x print(x[0])
... 
hello,world
i need help, python

如果要拆分字符串：

>>> for x in l:
...     print x[0].split(',')
... 
['hello', 'world']
['i need help', ' python']

阅读split