【问题标题】:python regular expression - re.findall() in listpython 正则表达式 - 列表中的 re.findall()
【发布时间】:2023-03-25 21:45:02
【问题描述】:

这是我的清单:

lista=[u'REG_S_3_UMTS_0_0 (RNC)', u'REG_S_3_UMTS_0_1 (RNC)', u'REG_S_3_UMTS_0_2 (RNC)', u'REG_S_2_GSM_NORT_CBSP_bsc_0_0 (BSC)', u'REG_S_2_GSM_NORT_CBSP_bsc_0_1 (BSC)', u'REG_S_2_GSM_NORT_CBSP_bsc_0_2 (BSC)', u'REG_S_3_GSM_ERIC_CBSP_bsc_0_0 (BSC)', u'REG_S_3_GSM_ERIC_CBSP_bsc_0_1 (BSC)', u'REG_S_3_GSM_ERIC_CBSP_bsc_0_2 (BSC)', u'REG_S_3_GSM_HUAP_CBSM_bsc_0_0 (BSC)', u'REG_S_3_GSM_HUAP_CBSM_bsc_0_1 (BSC)', u'REG_S_3_GSM_HUAP_CBSM_bsc_0_2 (BSC)', u'REG_S_3_GSM_HUA_CBSM_bsc_0_0 (BSC)', u'REG_S_3_GSM_HUA_CBSM_bsc_0_1 (BSC)', u'REG_S_3_GSM_HUA_CBSM_bsc_0_2 (BSC)', u'REG_S_3_GSM_IPAC_SABP_bsc_0_0 (BSC)', u'REG_S_3_GSM_IPAC_SABP_bsc_0_1 (BSC)', u'REG_S_3_GSM_IPAC_SABP_bsc_0_2 (BSC)', u'REG_S_3_GSM_NOKI_CLNS_bsc_0_0 (BSC)', u'REG_S_3_GSM_NOKI_CLNS_bsc_0_1 (BSC)', u'REG_S_3_GSM_NOKI_CLNS_bsc_0_2 (BSC)', u'REG_S_3_GSM_NOKI_RFC1_bsc_0_0 (BSC)', u'REG_S_3_GSM_NOKI_RFC1_bsc_0_1 (BSC)', u'REG_S_3_GSM_NOKI_RFC1_bsc_0_2 (BSC)', u'REG_S_3_GSM_NORT_CBSP_bsc_0_0 (BSC)', u'REG_S_3_GSM_NORT_CBSP_bsc_0_1 (BSC)', u'REG_S_3_GSM_NORT_CBSP_bsc_0_2 (BSC)', u'REG_S_3_GSM_SIEM_BSCI_bsc_0_0 (BSC)', u'REG_S_3_GSM_SIEM_BSCI_bsc_0_1 (BSC)', u'REG_S_3_GSM_SIEM_BSCI_bsc_0_2 (BSC)', u'REG_S_GSM_ERIC_CBSP_bsc_0_0 (BSC)', u'REG_S_GSM_ERIC_CBSP_bsc_0_1 (BSC)', u'REG_S_GSM_ERIC_CBSP_bsc_0_2 (BSC)', u'REG_S_GSM_HUAP_CBSM_bsc_0_0 (BSC)', u'REG_S_GSM_HUAP_CBSM_bsc_0_1 (BSC)', u'REG_S_GSM_HUAP_CBSM_bsc_0_2 (BSC)', u'REG_S_GSM_HUA_CBSM_bsc_0_0 (BSC)', u'REG_S_GSM_HUA_CBSM_bsc_0_1 (BSC)', u'REG_S_GSM_HUA_CBSM_bsc_0_2 (BSC)', u'REG_S_GSM_NORT_CBSP_bsc_0_0 (BSC)', u'REG_S_GSM_NORT_CBSP_bsc_0_1 (BSC)', u'REG_S_GSM_NORT_CBSP_bsc_0_2 (BSC)', u'Pool ID: 200']

这就是我的功能:

def Filter_List(lista):

     string = ''.join(lista)
     match = re.findall(r"\(([A-Z]+)\)|Pool ID", string)
     return match

结果我得到:

[u'RNC', u'RNC', u'RNC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'BSC', u'']

但是最后一个元素(应该是:Pool ID)没有显示。只有:u''。有谁知道我应该如何改变我的表情?提前谢谢!!!

【问题讨论】:

    标签: regex python-2.7


    【解决方案1】:

    请注意,如果正则表达式模式定义了捕获组,re.findall 将返回(列表)元组。删除它:

    import re
    lista=[u'REG_S_3_UMTS_0_0 (RNC)', u'REG_S_3_UMTS_0_1 (RNC)', u'REG_S_3_UMTS_0_2 (RNC)', u'REG_S_2_GSM_NORT_CBSP_bsc_0_0 (BSC)', u'REG_S_2_GSM_NORT_CBSP_bsc_0_1 (BSC)', u'REG_S_2_GSM_NORT_CBSP_bsc_0_2 (BSC)', u'REG_S_3_GSM_ERIC_CBSP_bsc_0_0 (BSC)', u'REG_S_3_GSM_ERIC_CBSP_bsc_0_1 (BSC)', u'REG_S_3_GSM_ERIC_CBSP_bsc_0_2 (BSC)', u'REG_S_3_GSM_HUAP_CBSM_bsc_0_0 (BSC)', u'REG_S_3_GSM_HUAP_CBSM_bsc_0_1 (BSC)', u'REG_S_3_GSM_HUAP_CBSM_bsc_0_2 (BSC)', u'REG_S_3_GSM_HUA_CBSM_bsc_0_0 (BSC)', u'REG_S_3_GSM_HUA_CBSM_bsc_0_1 (BSC)', u'REG_S_3_GSM_HUA_CBSM_bsc_0_2 (BSC)', u'REG_S_3_GSM_IPAC_SABP_bsc_0_0 (BSC)', u'REG_S_3_GSM_IPAC_SABP_bsc_0_1 (BSC)', u'REG_S_3_GSM_IPAC_SABP_bsc_0_2 (BSC)', u'REG_S_3_GSM_NOKI_CLNS_bsc_0_0 (BSC)', u'REG_S_3_GSM_NOKI_CLNS_bsc_0_1 (BSC)', u'REG_S_3_GSM_NOKI_CLNS_bsc_0_2 (BSC)', u'REG_S_3_GSM_NOKI_RFC1_bsc_0_0 (BSC)', u'REG_S_3_GSM_NOKI_RFC1_bsc_0_1 (BSC)', u'REG_S_3_GSM_NOKI_RFC1_bsc_0_2 (BSC)', u'REG_S_3_GSM_NORT_CBSP_bsc_0_0 (BSC)', u'REG_S_3_GSM_NORT_CBSP_bsc_0_1 (BSC)', u'REG_S_3_GSM_NORT_CBSP_bsc_0_2 (BSC)', u'REG_S_3_GSM_SIEM_BSCI_bsc_0_0 (BSC)', u'REG_S_3_GSM_SIEM_BSCI_bsc_0_1 (BSC)', u'REG_S_3_GSM_SIEM_BSCI_bsc_0_2 (BSC)', u'REG_S_GSM_ERIC_CBSP_bsc_0_0 (BSC)', u'REG_S_GSM_ERIC_CBSP_bsc_0_1 (BSC)', u'REG_S_GSM_ERIC_CBSP_bsc_0_2 (BSC)', u'REG_S_GSM_HUAP_CBSM_bsc_0_0 (BSC)', u'REG_S_GSM_HUAP_CBSM_bsc_0_1 (BSC)', u'REG_S_GSM_HUAP_CBSM_bsc_0_2 (BSC)', u'REG_S_GSM_HUA_CBSM_bsc_0_0 (BSC)', u'REG_S_GSM_HUA_CBSM_bsc_0_1 (BSC)', u'REG_S_GSM_HUA_CBSM_bsc_0_2 (BSC)', u'REG_S_GSM_NORT_CBSP_bsc_0_0 (BSC)', u'REG_S_GSM_NORT_CBSP_bsc_0_1 (BSC)', u'REG_S_GSM_NORT_CBSP_bsc_0_2 (BSC)', u'Pool ID: 200']
    string = ''.join(lista)
    match = re.findall(r"\([A-Z]+\)|Pool ID", string)
    print(match)
    

    this Python demo返回

    [u'(RNC)', u'(RNC)', u'(RNC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'(BSC)', u'Pool ID']

    【讨论】:

      猜你喜欢
      • 2021-09-30
      • 2012-02-18
      • 2012-06-19
      • 2020-05-16
      • 2016-09-27
      • 1970-01-01
      • 2012-09-02
      • 1970-01-01
      • 1970-01-01
      相关资源
      最近更新 更多