如何检查多个列表中内容的输入

Question

我可能有点菜鸟问题，但我如何检查“答案”的输入是否在多个列表中？我希望能够确定输入是否是“Vokalar”和“Konsonantar”的一部分。对于未来，我还希望能够确定输入是每个列表的一部分的次数。

Vokalar= ("a","e","i","o","u","y","æ","ø","å")
Konsonantar=("b","c","d","f","g","h","j","k","l","m","n","p","q","r","s","t","v","w","x","z")

Loop = 1

while Loop == 1:
    Answer = input("Word-check ;)")
    
    if Answer in Vokalar and Konsonantar:
        print("word")
    else:
        print("not word")

Answer 1

if Answer in Vokalar and Answer in Konsonantar:

但是，如果您稍后会有更多列表，您可以定义一个包含所有检查列表的变量并以这种方式检查：

check_lists = [Vokalar, Konsonantar, <other lists>]
if all(Answer in list_ for list_ in check_lists):

Answer 2

您必须检查答案字符串中的每个字符并将其与列表进行比较，而不是所有字符串

Vokalar= ("a","e","i","o","u","y","æ","ø","å")
Konsonantar= ("b","c","d","f","g","h","j","k","l","m","n","p","q","r","s","t","v","w","x","z")

Loop = 1

while Loop == 1:

Answer = input("Word-check : ")
isWord = True
for i in  Answer:
    if i in Vokalar or i in Konsonantar:
        pass
    else:
        isWord = False
if isWord :
    print("word")
else :
    print("not word")

Answer 3

# function to count number of occurences
def countOccurences(itemToCheck, itemsList):
    count = 0
    for item in itemsList:
        if item == itemToCheck:
            count += 1
    return count


Vokalar = ("a", "e", "i", "o", "u", "y", "æ", "ø", "å")
Konsonantar = ("b", "c", "d", "f", "g", "h", "j", "k", "l", "m",
               "n", "p", "q", "r", "s", "t", "v", "w", "x", "z")

Loop = 1

while Loop:
    Answer = input("Word-check ;)")

    if Answer in Vokalar and Answer in Konsonantar:
        vokalarOccurences = countOccurences(Answer, Vokalar)
        konsonantarOccurences = countOccurences(Answer, Konsonantar)
        print(f"{Answer} is found in both lists. Vokalar: {vokalarOccurences} times and Konsonantar: {konsonantarOccurences} times")

    elif Answer in Vokalar:
        vokalarOccurences = countOccurences(Answer, Vokalar)
        print(f"{Answer} is found in Vokalar list. Vokalar: {vokalarOccurences} times")

    elif Answer in Konsonantar:
        konsonantarOccurences = countOccurences(Answer, Konsonantar)
        print(f"{Answer} is found in Konsonantar list. Konsonantar: {konsonantarOccurences} times")

    else:
        print(f"{Answer} not found in any list.")

Answer 4

要检查答案是否是单词，您可以使用字符串isalpha 的内置方法：https://docs.python.org/3/library/stdtypes.html#str.isalpha

如果您想手动操作，最好使用sets：

def check_answer(answer: str) -> bool:
    cur_set = set(answer)
    vok = set(Vokalar) & cur_set
    kon = set(Konsonantar) & cur_set
    return len(cur_set) == len(vok) + len(kon) # len must be equal to sum of vok and kon to be a correct word

为了计算出现次数，有一个内置集合（一个特殊的字典）： https://docs.python.org/3/library/collections.html#collections.Counter

from collections import Counter

c = Counter(answer)
print(c.keys())
print(c.get('a', 0))  # to get the count for a char

然后，您可以检查每个计数在哪个列表中并打印计数器：

for elm, count in c.items():
    if elm in Vokalar:
        print(elm, "in Vokalar", count, "times")
    elif elm in Konsonantar:
        print(elm, "in Konsonantar", count, "times")

请注意，您不使用这些列表管理大小写，但 isalpha 方法可以做到...

Answer 5

要计算两个列表中答案的出现次数，您可以使用代码：

cnt_vokalar = Vokalar.count(Answer)
cnt_konsonantar = Konsonantar.count(Answer)

然后你可以检查出现次数是否大于0：

while Loop == 1:
    Answer = input("Word-check ;)")
    cnt_vokalar = Vokalar.count(Answer)
    cnt_konsonantar = Konsonantar.count(Answer)
    if cnt_vokalar > 0 and cnt_konsonantar > 0:
        print("word")
    else:
        print("not word")