遍历所有 csv 文件的目录并为每个单独的（csv）文件创建 kml 并使用文件名保存

【问题标题】：Iterating through directory for all csv files and creating kml for each individual(csv) file and save using file name遍历所有 csv 文件的目录并为每个单独的（csv）文件创建 kml 并使用文件名保存
【发布时间】：2020-05-20 18:12:34
【问题描述】：

import csv
import simplekml
import pandas as pd
import glob

frame = pd.DataFrame()
filelist=glob.glob('/Users/germanportes/Documents/Status_Report/Telework_training/Anomaly_6/files/*.csv')
kml = simplekml.Kml()
for file in filelist:
    a6 =pd.read_csv(file)
    for row in a6:
        kml.newpoint(name=a6['idfa'], description = a6['device_os'],coords = [(a6['longitude'], a6['latitude'])])
kml.save('/Users/germanportes/Documents/Status_Report/Telework_training/Anomaly_6/files/kml/'+str(a6)+'.csv')

我喜欢使用文件名将每个单独的 csv 保存为自己的 kml

【问题讨论】：

标签： python pandas glob simplekml

【解决方案1】：

在这里，您将遍历列而不是行，然后将 pandas.Series 作为列传递给 kml.newpoint 参数而不是某些值。使用 DataFrame.apply() 遍历数据框行，并为您的 kml 对象每行添加一个点，如下所示：

from os.path import join
from glob import iglob
from pathlib import Path

import simplekml
import pandas as pd

csv_dir = 'path/to/csv/directory'
kml_dir = 'path/to/kml/directory'

for file in iglob(join(csv_dir, '*.csv')):
    # read the csv file
    df = pd.read_csv(file)
    # make an empty kml object
    kml = simplekml.Kml()
    # iterate over the rows and and add new points to kml
    df.apply(lambda x: kml.newpoint(name=x['idfa'], description = x['device_os'], coords=[(x['longitude'], x['latitude'])]), axis=1)
    # save it as kml with the csv filename
    kml.save(join(kml_dir, '{}.kml'.format(Path(file).stem)))

【讨论】：