python 正则表达式字符串拆分

Question

以这种方式拥有数据

data1 = 'Seattle, WA 98108'
data2 = 'SeattleWA 98108'
data3 = 'Seattle, WA98108'
data3 = 'Seattle, WA   98108'

如何拆分所有案例以获取数据：

city = 'Seattle'
state = 'WA'
zip = '98108'

当然有很多不同的城市

Answer 1

使用re.findall

re.findall(r'^[A-Z][a-z]+|[A-Z]+|\d+', s)

例子：

>>> def split_c(s):
    return re.findall(r'^[A-Z][a-z]+|[A-Z]+|\d+', s)

>>> split_c('Seattle, WA 98108')
['Seattle', 'WA', '98108']
>>> split_c('SeattleWA 98108')
['Seattle', 'WA', '98108']
>>> split_c('Seattle, WA98108')
['Seattle', 'WA', '98108']
>>> split_c('Seattle, WA   98108')
['Seattle', 'WA', '98108']
>>> city, state, zip_ = split_c('Seattle, WA   98108')
>>> city
'Seattle'
>>> state
'WA'
>>> zip_
'98108'
>>>