如何在 python 3.5 中使我的“Lingo”游戏正常工作？

Question

游戏与行话略有不同，因为可以使用任何字长。我怎样才能让我的程序打印一个？当字母在单词中但不在正确的位置时？如果字母在正确的位置，我如何让它打印实际的字母？例如单词是“tank”并且用户输入“town”它应该打印“t--？”我让一切正常工作，直到我必须让我的代码输出除“-”以外的字符 （这些词是荷兰语，但这不应该有任何区别）

import random
wordlist = ["hond", "haas", "neus", "peer","fruit", "laptop","raam","computer", "python", "hakan", "akkas", "mohammed", "amine", "school","informatica"]
word = random.choice(wordlist)
print("Your secret word has ", len(word), "letters")
while True:
    guessword = input("Guess the word:")
    if len(Guessword) != len(word): print("type a word with", len(word),"letters")
    elif guessword == word: break
    elif guessword != word:
        if guessword != word:  print("-" * len(word))
print("Congratulations, you guessed the word correctly!")

我还必须让游戏告诉你猜单词需要多少回合，并实施基于休息时间的评分系统。

编辑：必须尽可能紧凑

Answer 1

一种使用enumerate的方法：

import random
wordlist = ["hond", "haas", "neus", "peer","fruit", "laptop","raam","computer", "python", "hakan", "akkas", "mohammed", "amine", "school","informatica"]
# 'word' hardcoded for testing
word = "tank" #random.choice(wordlist)
print("Your secret word has ", len(word), "letters")
while True:
    guessword = input("Guess the word:")
    if len(guessword) != len(word): print("type a word with", len(word),"letters")
    elif guessword == word: break
    elif guessword != word:
        for position, letter in enumerate(guessword):
            if letter == word[position]:
                print(letter, end="")
            elif letter not in word:
                print("-", end="")
            else:
                print("?", end="")
        print("")
print("Congratulations, you guessed the word correctly!")

测试：

$ python3.5 word_game.py 
Your secret word has  4 letters
Guess the word:town
t--?
Guess the word:tans
tan-
Guess the word:tank
Congratulations, you guessed the word correctly!