将包含时区的字符串秒转换为格式化的字符串日期

Question

我正在尝试将如下所示的字符串秒数动态转换为字符串日期。

'1545239561 +0100'

问题是最后插入的时区，我找不到任何使用良好格式从该字符串中检索日期的python时间对象方法。

我的尝试：

>>>seconds = '1545239561 +0100'
>>>time.strftime('%y%m%d-%H%M%S-%f', datetime.datetime.fromtimestamp(seconds)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: an integer is required (got type str)
>>>time.strptime(seconds)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/local/Cellar/python/3.6.4_3/Frameworks/Python.framework/Versions/3.6/lib/python3.6/_strptime.py", line 559, in _strptime_time
    tt = _strptime(data_string, format)[0]
  File "/usr/local/Cellar/python/3.6.4_3/Frameworks/Python.framework/Versions/3.6/lib/python3.6/_strptime.py", line 362, in _strptime
    (data_string, format))
ValueError: time data '1545239561 +0100' does not match format '%a %b %d %H:%M:%S %Y'
>>>time.strptime(seconds, "%S +%Z")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/local/Cellar/python/3.6.4_3/Frameworks/Python.framework/Versions/3.6/lib/python3.6/_strptime.py", line 559, in _strptime_time
    tt = _strptime(data_string, format)[0]
  File "/usr/local/Cellar/python/3.6.4_3/Frameworks/Python.framework/Versions/3.6/lib/python3.6/_strptime.py", line 362, in _strptime
    (data_string, format))
ValueError: time data '1545239561 +0100' does not match format '%S +%Z'

Answer 1

我会尝试分别处理这两个值并将它们合并为单个 datetime:

>>>from datetime import datetime
>>>s = '1545239561 +0100'
>>>seconds, offset = s.split()
>>>datetime.fromtimestamp(int(seconds)).replace(tzinfo=datetime.strptime(offset, "%z").tzinfo)
datetime.datetime(2018, 12, 19, 17, 12, 41, tzinfo=datetime.timezone(datetime.timedelta(0, 3600)))

Answer 2

是的@mfrackwiak...

我这样做了

>>> epoch = "1545239561 +0100"
>>> seconds, offset = epoch.split()
>>> datetime.fromtimestamp(int(seconds)).replace(tzinfo=datetime.strptime(offset, "%z").tzinfo).strftime('%Y-%m-%d %H:%M:%S-%Z')
'2018-12-19 18:12:41-UTC+01:00'
>>> 

Answer 3

你可以试试下面的例子：

from datetime import datetime,timedelta
# split the timevalue and offset value
ss = '1545239561 +0100'.split()
format =  "%A, %B %d, %Y %I:%M:%S"
# calculate the hour and min in the offset
hour  = int(ss[1][0:2])
min =   int(ss[1][2:])
# calculate the time from the sec and convert it to datetime object
time_from_sec = datetime.strptime(datetime.fromtimestamp(int(ss[0])).strftime(
    format), format)
# add the offset delta value to the time calculated
time_with_delta_added = time_from_sec + timedelta(hours=hour,minutes=min)
print(time_with_delta_added)

输出：

2018-12-19 12:22:41