如何将while循环中的列表附加到python中的同一列表中 - selenium

Question

简而言之，我的问题是我想从“n”个邮箱中获取收到的消息并将邮箱（及其消息）一个接一个地附加到彼此，然后我想作为数据帧打印到一个excel文件。 （例如 n =5）

mailbox_list = ['mailbox_1','mailbox_2','mailbox_3','mailbox_4','mailbox_5']

这是我的代码，适用于一个邮箱的内容：

i = 0  # starting number of mailboxes
while i < len(mailbox_list): # I want to get messages for all mailboxes one by one 
    try:
        # get the message content 
        rm_content = driver.find_element(By.XPATH, '//*[@id="content"]/messages/div[2]/div/div/table')
        time.sleep(1)
        messages = (rm_content.text.split('\n')) # these are the messages 
        print('Messages found')
        
        # add these messages to a list
        msg_list = [messages[i:i + 3] for i in range(2, len(messages), 3)]  
        # (!!!) this list contains the messages for 1 mailbox that I want to append to the next item in the while loop
        
        # use a dataframe for messages
        df_msg_list = pd.DataFrame(msg_list)
        df_msg_list.columns = ['Sender', 'Content', 'Date']
        df_msg_list[['Inbox', 'Query_Date']] = pd.DataFrame([[get_key(f'{mailbox_list[i]}'), date]], index=df_msg_list.index)
        print(df_msg_list)

        # write into excel
        writer = pd.ExcelWriter(messages_excel, engine='xlsxwriter')
        df_msg_list.to_excel(writer, sheet_name=f'{date[0:10]}', header=True, index=False)
        writer.save()
        
    except NoSuchElementException:
        pass # exception handling
        print('No messages found')
    
    i=i+1

有人可以帮助我如何将 msg_list 附加到 while 循环中的下一项（下一个 msg_list）吗？

Answer 1

您可以定义并保留一些全局变量，我们将其称为循环外的total_msg_list，并将循环中的当前msg_list 附加到该全局变量。
像这样的：

total_msg_list = []
i = 0  # starting number of mailboxes
while i < len(mailbox_list): # I want to get messages for all mailboxes one by one 
    try:
        # get the message content 
        rm_content = driver.find_element(By.XPATH, '//*[@id="content"]/messages/div[2]/div/div/table')
        time.sleep(1)
        messages = (rm_content.text.split('\n')) # these are the messages 
        print('Messages found')
        
        # add these messages to a list
        msg_list = [messages[i:i + 3] for i in range(2, len(messages), 3)]  
        total_msg_list.append(msg_list)
        
        # use a dataframe for messages
        df_msg_list = pd.DataFrame(msg_list)
        df_msg_list.columns = ['Sender', 'Content', 'Date']
        df_msg_list[['Inbox', 'Query_Date']] = pd.DataFrame([[get_key(f'{mailbox_list[i]}'), date]], index=df_msg_list.index)
        print(df_msg_list)

        # write into excel
        writer = pd.ExcelWriter(messages_excel, engine='xlsxwriter')
        df_msg_list.to_excel(writer, sheet_name=f'{date[0:10]}', header=True, index=False)
        writer.save()
        
    except NoSuchElementException:
        pass # exception handling
        print('No messages found')
    
    i=i+1
#now, after the loop completed you can see the final content of total_msg_list
print(total_msg_list)