Django - “模块”对象不可调用答案

【问题标题】：Django - 'module' object is not callableDjango - “模块”对象不可调用
【发布时间】：2018-01-20 20:29:39
【问题描述】：

我正在尝试使用 django 提供数据库中的图像，但是当我添加时

+ static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)

到我的 urlpatterns 我得到这个错误：TypeError at /: module object is not callable

这是回溯：

File "/home/watch/Documents/projects/herokuapp/venv/lib/python3.6/site-packages/django/core/handlers/exception.py" in inner
  35.             response = get_response(request)

File "/home/watch/Documents/projects/herokuapp/venv/lib/python3.6/site-packages/django/core/handlers/base.py" in _get_response
  113.         resolver_match = resolver.resolve(request.path_info)

File "/home/watch/Documents/projects/herokuapp/venv/lib/python3.6/site-packages/django/urls/resolvers.py" in resolve
  494.             for pattern in self.url_patterns:

File "/home/watch/Documents/projects/herokuapp/venv/lib/python3.6/site-packages/django/utils/functional.py" in __get__
  36.         res = instance.__dict__[self.name] = self.func(instance)

File "/home/watch/Documents/projects/herokuapp/venv/lib/python3.6/site-packages/django/urls/resolvers.py" in url_patterns
  536.         patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)

File "/home/watch/Documents/projects/herokuapp/venv/lib/python3.6/site-packages/django/utils/functional.py" in __get__
  36.         res = instance.__dict__[self.name] = self.func(instance)

File "/home/watch/Documents/projects/herokuapp/venv/lib/python3.6/site-packages/django/urls/resolvers.py" in urlconf_module
  529.             return import_module(self.urlconf_name)

File "/usr/lib/python3.6/importlib/__init__.py" in import_module
  126.     return _bootstrap._gcd_import(name[level:], package, level)

File "<frozen importlib._bootstrap>" in _gcd_import
  994. <source code not available>

File "<frozen importlib._bootstrap>" in _find_and_load
  971. <source code not available>

File "<frozen importlib._bootstrap>" in _find_and_load_unlocked
  955. <source code not available>

File "<frozen importlib._bootstrap>" in _load_unlocked
  665. <source code not available>

File "<frozen importlib._bootstrap_external>" in exec_module
  678. <source code not available>

File "<frozen importlib._bootstrap>" in _call_with_frames_removed
  219. <source code not available>

File "/home/watch/Documents/projects/herokuapp/mysite/mysite/urls.py" in <module>
  27. ]+ static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)

Exception Type: TypeError at /
Exception Value: 'module' object is not callable

我尝试在主 urls.py 和应用程序 urls.py 中都使用它，但它不起作用。

我的 media_root 和 media_url 如下：

abspath = lambda *p: os.path.abspath(os.path.join(*p))

PROJECT_ROOT = abspath(os.path.dirname(__file__))

MEDIA_ROOT = abspath(PROJECT_ROOT, 'media')
MEDIA_URL = '/media/'

我尝试用

重新导入所有内容

from django.conf.urls import *

但它也没有工作。

编辑，这些是我的导入：

from django.conf.urls import url, include
from django.contrib import admin
from django.conf.urls import static
from django.conf import settings

我正在使用最新版本的 django 并在 heroku 中部署（本地与 heroku local）

【问题讨论】：

您需要在该文件中显示您正在使用的导入。您导入static 的程度如何准确？

标签： python django heroku

【解决方案1】：

改变

from django.conf.urls import static

到

from django.conf.urls.static import static

你可以走了。

【讨论】：

【解决方案2】：

from django.conf.urls.static import static

写下这一行，而不是

from django.conf.urls import static

【讨论】：

您好，您可以使用代码块来格式化您的代码，使其更具可读性，例如：python from django.conf.urls.static import static