【发布时间】:2016-07-30 02:08:36
【问题描述】:
我正在尝试覆盖get_bundle_detail_data
class MyResourse(ModelResource):
foo = fields.CharField( attribute = 'modelA__variableOnModelA' )
def get_bundle_detail_data(self, bundle):
return bundle.obj.foo
class Meta:
resource_name='resource'
使用代码行foo = fields.CharField( attribute = 'modelA__variableOnModelA' ),我将资源MyResource 上的变量foo 设置为modelA 上名为variableOnModelA 的变量。这很好用。
但我试图让variableOnModelA 成为MyResource 的标识符,这样我可以使用/api/v1/resource/bar/ 来获取详细的MyResource,并将变量foo 设置为bar。
我遇到的问题是错误:Invalid resource lookup data provided (mismatched type).这个错误是什么意思?
终极问题:如何将foo 用作detail_uri_name?
编辑 型号:
class AgoraUser(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE, primary_key=True, related_name='agora_user')
class Meta:
db_table = 'agora_users'
网址:
full_api = Api(api_name='full')
full_api.register(AgoraUserResourse())
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^', include(full_api.urls)),
url(r'^', include(min_api.urls)),
url(r'^search/', include('haystack.urls')),
url(r'^accounts/login/$', auth_views.login, {'template_name': 'login.html'}, name='login'),
]
实际资源:
class AgoraUserResourse_min(ModelResource):
username = fields.CharField(attribute = 'user__username' )
class Meta:
resource_name='user'
#detail_uri_name = 'user__username'
queryset = AgoraUser.objects.all()
allowed_methods = ['get', 'put', 'post']
authentication = AgoraAuthentication()
authorization = AgoraAuthorization()
def get_bundle_detail_data(self, bundle):
return bundle.obj.username
【问题讨论】:
-
你能粘贴你的模型和 URL 配置吗?
标签: python django model tastypie