我只能检查二维数组的第一列答案

【问题标题】：I only can check the first column of an 2D array我只能检查二维数组的第一列
【发布时间】：2020-02-10 17:02:58
【问题描述】：

我用精灵写了那个记忆谜题，我有一些错误： 1.- 当我将鼠标移到框上时，只有第一列显示突出显示效果。 2.- 同样，只有第一列显示了被覆盖的盒子的效果

我认为问题在于函数：

def cartesianToPositional(x, y):
    '''
    That function is used to check if the mouse is over a box. In that case, the function return the position of the 
    box on which is over in the 2D list positional order
    '''
    for boxx in range(COLUMNS):
        for boxy in range(ROWS):
            left, top = positionalToCartesian(boxx, boxy)
            boxRect = pygame.Rect(left, top, BOXSIZE, BOXSIZE)
            if boxRect.collidepoint(x, y): # That method is used to check if the x, y position is colliding with the boxRect
                return (boxx, boxy)
        return (None, None)

def drawHighlightBox(boxx, boxy):
    '''
    This function draw a perimether around the box passed with the highlightcolor
    '''
    left, top = positionalToCartesian(boxx, boxy)
    pygame.draw.rect(DISPLAY, HIGHLIGHTCOLOR, (left - 5, top - 5, BOXSIZE + 10, BOXSIZE + 10), 4) # 4 is for the width of the line

def drawBoxCovers(board, boxes, cover):
    '''
    This function cover the icons if is needed
    '''
    for box in boxes:
        left, top = positionalToCartesian(box[0], box[1])
        pygame.draw.rect(DISPLAY, BGCOLOR, (left, top, BOXSIZE, BOXSIZE))
        ball = getBall(board, box[0], box[1])
        drawIcon(ball, box[0], box[1])
        if cover > 0: 
            pygame.draw.rect(DISPLAY, BOXCOLOR, (left, top, BOXSIZE, BOXSIZE))
    pygame.display.update()
    FPSCLOCK.tick(FPS)

【问题讨论】：

请修正你的缩进。

标签： python python-3.x pygame

【解决方案1】：

这是一个Indentation 问题。在cartesianToPositional 中，return 语句（return (None, None)）必须在函数的末尾，而不是在外循环中：

def cartesianToPositional(x, y):

    for boxx in range(COLUMNS):
        for boxy in range(ROWS):
            left, top = positionalToCartesian(boxx, boxy)
            boxRect = pygame.Rect(left, top, BOXSIZE, BOXSIZE)
            if boxRect.collidepoint(x, y): 
                return (boxx, boxy)

    # <--
    return (None, None)

【讨论】：

【解决方案2】：

在您的源代码中，您的某个函数会提前返回。

def cartesianToPositional(x, y):
    '''
    That function is used to check if the mouse is over a box. In that case, the function return the position of the 
    box on which is over in the 2D list positional order
    '''
    for boxx in range(COLUMNS):
        for boxy in range(ROWS):
            left, top = positionalToCartesian(boxx, boxy)
            boxRect = pygame.Rect(left, top, BOXSIZE, BOXSIZE)
            if boxRect.collidepoint(x, y): # That method is used to check if the x, y position is colliding with the boxRect
                return (boxx, boxy)
        # This prevents your outer for loop from completing
        return (None, None)

删除return (none, None) 上的一级缩进，它应该可以正常工作。

【讨论】：