仅在一种条件下打破两个嵌套循环

Question

这是我的代码

login = input("Whats the keyword?\n")

if login == "3faze":
    print("Ok I will give you access!")
    access = True
else:
    print("Wrong! Try opening the program again!")
    t.sleep(5)
    access = False

if access == True:
        while True:
                action = input("What do you want to do?")
                if action == "get passwords" or action == "Get Passwords" or action == "Get passwords" or action == "get Passwords":
                        print("Ok")
                        while True:
                                which = input("Which password do you want to get?")

                                if which == "google" or which == "Google":
                                    print(str(passwords[0] + passwords[1] + passwords[2] + passwords[3] + passwords[4]))
                                    close = input("Do you want to close?")
                                    if close == "yes" or close == "Yes" or close == "yea" or close == "Yea" or close == "yea":
                                        break
                                        
                                        t.sleep(1)
                                    else:
                                        print("Ok")
                                        t.sleep(1)

在哪里说 break 我想打破两个嵌套循环。 感谢帮助的人。 我是为密码管理器制作的，因为您可能会说那里还有更多代码，但我不想显示它，因为它有我的密码，如果需要，我将制作一个没有这些密码的模板。

Answer 1

您可以将 while True 更改为变量并更改其布尔值以中断

password_found = False

while not password_found:
    ...
    while not password_found:
        close = input()
        if close == 'yes':
            password_found = True

Answer 2

根据您的代码，我尝试进行修改以将两个循环合并为一个。

您可以根据需要将if close...:中的continue替换为break。

login = input("Whats the keyword?\n")

if login == "3faze":
    print("Ok I will give you access!")
    access = True
else:
    print("Wrong! Try opening the program again!")
    t.sleep(5)
    access = False

if access is True:
    skip = False
    while True:
        if not skip:
            action = input("What do you want to do?")
            if action == "get passwords" or action == "Get Passwords" or action == "Get passwords" or action == "get Passwords":
                print("Ok")
                skip = True
            else:
                continue

        which = input("Which password do you want to get?")
        if which == "google" or which == "Google":
            print(str(passwords[0] + passwords[1] + passwords[2] + passwords[3] + passwords[4]))
            close = input("Do you want to close?")
            if close == "yes" or close == "Yes" or close == "yea" or close == "Yea" or close == "yea":
                t.sleep(1)
                skip = False
                continue
                # break

            else:
                print("Ok")
                t.sleep(1)

Answer 3

您可以再添加一个布尔变量，并将中间的while 循环替换为while var_name。

    login = input("Whats the keyword?\n")
    
    if login == "3faze":
        print("Ok I will give you access!")
        access = True
    else:
        print("Wrong! Try opening the program again!")
        t.sleep(5)
        access = False
    
    if access == True:
            leave = False
            while not leave:
                    action = input("What do you want to do?")
                    if action == "get passwords" or action == "Get Passwords" or action == "Get passwords" or action == "get Passwords":
                            print("Ok")
                            while True:
                                    which = input("Which password do you want to get?")
    
                                    if which == "google" or which == "Google":
                                        print(str(passwords[0] + passwords[1] + passwords[2] + passwords[3] + passwords[4]))
                                        close = input("Do you want to close?")
                                        if close == "yes" or close == "Yes" or close == "yea" or close == "Yea" or close == "yea":
                                            leave = True
                                            
                                            t.sleep(1)
                                        else:
                                            print("Ok")
                                            t.sleep(1)

除此之外，您可以只检查close.lower() == "yes"，而不是检查每个string 的可能性（例如Yes 或yes）。

Answer 4

还有 2 条提示： 您可以将输入转换为小写，这样您就不必将其与两个版本进行比较，例如：

如果 action == "获取密码" 或 action == "获取密码" -> if action.lower() == '获取密码'

1. 有比
更好的选择

passwords[0] + passwords[1] + passwords[2] + passwords[3] + passwords[4]

但不清楚“密码”是什么（字符串、字母列表、数字列表？）

Answer 5

尝试使用函数并用 return 打破循环。 例如：

def sample():
    while True:
        while True:
            if condition:
                return

然后使用代码中的函数：

sample()

Answer 6

我对您的问题的解释，我做了一些清理，使代码对我来说更具可读性，但这是个人决定：

actionLst = ("get passwords", "Get Passwords", "Get passwords", "get Passwords")
yesLst = ("yes", "Yes", "yea", "Yea", "yea")
googleLst = ("google", "Google")

login = input("Whats the keyword?\n")

if login == "3faze":
    print("Ok I will give you access!")
    access = True
else:
    print("Wrong! Try opening the program again!")
    t.sleep(5)
    access = False

FirstTime = True
while access: # at this level already invariant , 
              # don't use it in the loop itself !
    if FirstTime:
        action = input("What do you want to do?")
        if action in actionLst: print("Ok") 
        else: continue
        FirstTime = False
    else:
        which = input("Which password do you want to get?")
        if which in googleLst:
            print(str(passwords[0] + passwords[1] + passwords[2] + passwords[3] + passwords[4]))
            close = input("Do you want to close?")
            if close in yesLst:
                break
                t.sleep(1)
            else:
                print("Ok")
                t.sleep(1)
                # if you don't close will loop again !?
                # so is not bulletproof ...

Answer 7

尝试在外循环的最后一行添加第二个 break 关键字。