从数组python中选择多个元素

Question

这是一个非常基本的问题，但这里是：

我想创建一个数组，然后想将用户输入与数组中的那些元素进行比较。

如果匹配一个元素，则函数 1 将运行。如果数组中的两个元素匹配，则将运行替代函数，依此类推。

目前我只能使用没有指向数组的链接的 IF 语句，如下所示：

def stroganoff():
    print ("You have chosen beef stroganoff")
    return

def beef_and_ale_pie():
    print ("You have chosen a beef and ale pie")
    return

def beef_burger():
    print ("You have chosen a beef burger")
    return

ingredients = ['beef','mushrooms','ale','onions','steak','burger']

beef = input("Please enter your preferred ingredients ")

if "beef" in beef and "mushrooms" in beef:
    stroganoff()
elif "beef" in beef and "ale" in beef:
    beef_and_ale_pie()
elif "beef" in beef and "burger" in beef:
    beef_burger()

如前所述，这对你们中的一些人来说是基本的东西，但感谢您的关注！

Answer 1

因为你只能使用 IF 语句

beef=input().split()
#this splits all the characters when they're space separated
#and makes a list of them

您可以使用您的"beef" in beef and "mushrooms" in beef，它应该会按照您的预期运行

Answer 2

所以我理解你的问题，所以你想知道，用户输入了多少ingredients：

ingredients = {'beef','mushrooms','ale','onions','steak','burger'}

# assume for now the inputs are whitespace-separated:
choices = input("Please enter your preferred ingredients ").split()

num_matches = len(ingredients.intersection(choices))
print('You chose', num_matches, 'of our special ingredients.')

Answer 3

你可以这样做：

# Dictionary to map function to execute with count of matching words
check_func = {
    0: func_1,
    1: func_2,
    2: func_3,    
} 

ingredients = ['beef','mushrooms','ale','onions','steak','burger']
user_input = input()

# Convert user input string to list of words
user_input_list = user_input.split()

# Check for the count of matching keywords
count = 0
for item in user_input_list:
    if item in ingredients:
        count += 1

# call the function from above dict based on the count
check_func[count]()