使用来自另一个函数 python3 的值答案

【问题标题】：Use values from another function python3使用来自另一个函数 python3 的值
【发布时间】：2021-01-23 17:26:09
【问题描述】：

我有这段代码，但我不知道如何在另一个函数中使用用户的“年龄”，知道我有什么问题吗？

def accounts():
    yourCode = input("Please enter your user code. \nIf you already have an account, type your account user code. \nOtherwise, enter a new one to create an account: ")

   
    with open("users.txt", "r") as rf:
        users = rf.readlines() 
        for each_user in [user.split(",") for user in users]: 
            if each_user[0] == yourCode: 
                print(f"Welcome {each_user[1]}") 
                age = each_user[2]
                xxApp() 
                return None 
    with open("users.txt", "a") as af:
        name = input("Please enter your name: ")
        age = input("Enter your age: ")
        af.write(f"{yourCode},{name},{age}\n") 
        print(f"Thank you {name}, your information has been added.")
        xxApp()


def xxApp():
    age = each_user[2]
    print(age)

【问题讨论】：

标签： python python-3.x function

【解决方案1】：

作为参数传递

def accounts():
    yourCode = input("Please enter your user code. \nIf you already have an account, type your account user code. \nOtherwise, enter a new one to create an account: ")

   
    with open("users.txt", "r") as rf:
        users = rf.readlines() 
        for each_user in [user.split(",") for user in users]: 
            if each_user[0] == yourCode: 
                print(f"Welcome {each_user[1]}") 
                xxApp(each_user) 
                return None 
    ...


def xxApp(user):
    age = user[2]
    print(age)

【讨论】：

【解决方案2】：

您正在定义age = each_user[2]，但each_user 变量仅在accounts() 的范围内可用。

You can read about python scopes here

我会修改xxApp() 函数以接受一个变量作为这样的参数

def xxApp(each_user):
    age = each_user[2]
    print(age)

然后你调用xxApp()，将each_user作为参数传递，所以它在xxApp()的范围内可用，就像这样xxApp(each_user)

【讨论】：